Answer: 2 seconds
Explanation:
Given that,
Time (T) = ?
Charge (Q) = 4 coulombs
current (I) = 2 Amps
Since charge depends on the amount of current flowing through the wire in a given time, hence
Charge = Current x Time
Q = IT
4 coulombs = 2 Amps x Time
Time = 4 coulombs / 2 Amps
Time = 2 seconds
Thus, it takes 2 seconds for the current to flow through the wire
Each capacitor carry the same charge 'q'.
Discussion:
The voltage from the battery is distributed equally across all of the capacitors when they are linked in series. The three identical capacitors' combined voltage is computed as follows:
= V₁ +V₂ +V₃
This voltage may also be calculated using capacitance and charge;
V = Q/ C
= V₁ +V₂ +V₃
Provided that the total charge is 'q', hence the total voltage can be expressed as:
= (Q/C₁) + (Q/C₂) + (Q/C₃) = Q(1/C₁ +1/C₂ +1/C₃)
Therefore from the above explanation, it is concluded that each and every capacitor carry same charge 'q'.
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Answer:
at resonance impedence is equal to resistance and quality factor is dependent on R L AND C all
Explanation:
we know that for series RLC circuit impedance is given by

but we know that at resonance
putting
in impedance formula , impedance will become
Z=R so at resonance impedance of series RLC is equal to resistance only
now quality factor of series resonance is given by
so from given expression it is clear that quality factor depends on R L and C
A pH scale goes from 0 - 14.
7 is in the middle so it is neutral
The resistance of a given conductor depends on its electrical resistivity (
), its length(L) and its cross-sectional area (A), as follows:

In this case, we have
,
and
. So, the total resistance of the wire with length of 138m is:
