All categories

2 years ago

If the car goes exits a freeway and goes from 65 mph to 35 mph is it accelerating?

Physics

1 answer:

Zolol [24]2 years ago

8 0

Answer:

No, the car is decelerating

Explanation:

No the car is decelerating if it exits a freeway and goes from 65

mph to 35 mph since the change in velocity is negative.

change in velocity = final - initial

change in velocity = 35 - 65

change in velocity = -30mph

Since the change in velocity is negative, hence the car is decelerating. Deceleration is a negative acceleration

You might be interested in

The distance between two charged objects is doubled. What happens to the electrostatic force between the two?a)It will double.b)

zzz [600]

Answer:

d) It will be cut to a fourth of the original force.

Explanation:

The magnitude of the electrostatic force between the charged objects is

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the separation between the two objects

In this problem, the initial distance is doubled, so

r' = 2r

Therefore, the new electrostatic force will be

$F=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}(k\frac{q_1 q_2}{r^2})=\frac{1}{4}F$

So, the force will be cut to 1/4 of the original value.

5 0

2 years ago

A 125kg man buy a 6kg watermelon, a 3kg cantaloupe, and 6kgs of potatoes, he walks home with his purchases in a large bag. His w

Stells [14]

Answer:

350N

Explanation:

Given parameters:

Mass of the man = 125kg

Mass of the watermelon = 6kg

Mass of cantaloupe = 3kg

Mass of potatoes = 6kg

Acceleration = 2.5m/s²

Unknown:

Force required to get home = ?

Solution:

To find this force we use;

Force = mass x acceleration

mass = 125 + 6 + 3 + 6 = 140kg

So;

Net force = 140 x 2.5 = 350N

5 0

2 years ago

A 65.0 kg ice skater standing on frictionless ice throws a 0.15 kg snowball horizontally at a speed of 32.0 m/s. What is the vel

spin [16.1K]

Answer:

(d) 0.07 m/s

Explanation:

Given Data

Snowball mass m₁=0.15 kg

Ice skater mass m₂=65.0 kg

Snowball velocity v₁=32.0 m/s

To find

Velocity of Skater v₂=?

Solution

From law of conservation of momentum

$m_{1}v_{1}=m_{2}v_{2}\\ v_{2}=\frac{m_{1}v_{1}}{m_{2}}\\ v_{2}=\frac{(0.15kg)(32.0m/s)}{65.0kg}\\ v_{2}=0.0738m/s\\or\\v_{2}=0.07 m/s$

So Option d is correct one

5 0

2 years ago

A displacement vector 5 units long makes an angle of 67° with the x-axis. What is the horizontal component of displacement?

Harman [31]

Yo sup??

magnitude of original vector is 5 units.

angle made with x axis is 67°

horizontal component=5*cos67°

=5*0.4

=2 units (approx)

Therefore the correct answer is option B

Hope this helps

7 0

2 years ago

Read 2 more answers

find the period of a simple pendulum of 1m length placed on earth and on moon g on moon =1.67m/s² g on earth=10m/s²

Ierofanga [76]

Answer:

$T_{m }$ = 4.86 s

$T_{e}$ = 1.98 s

Explanation:

Given:

Length = l = 1 m

Acceleration due to gravity of moon = $g_{m}$ = 1.67 m/s²

Acceleration due to gravity of Earth = $g_{e}$ = 10 m/s²

Required:

Time period = T = ?

Formula:

T = 2π $\sqrt{\frac{l}{g} }$

Solution:

For moon

Putting the givens,

T = 2(3.14) $\sqrt{\frac{1}{1.67} }$

T = 6.3 $\sqrt{0.6}$

T = 6.3 × 0.77

T = 4.86 sec

For Earth,

Putting the givens

T = 2π $\sqrt{\frac{1}{10} }$

T = 2(3.14) $\sqrt{0.1}$

T = 6.3 × 0.32

T = 1.98 sec

3 0

2 years ago