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3 years ago

Which sentence features a shift in tense?

Physics

2 answers:

Naddika [18.5K]3 years ago

7 0

C ........................................

Ganezh [65]3 years ago

4 0

The answer is c. It starts in the past by saying he "bought" then shifts to present by saying "goes" and "buys" but then shifts back to past by saying "last week"

hope this helps

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A virtual image produced by a lens is always

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3 years ago

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Two charged concentric spherical shells have radii of 11.0 cm and 14.0 cm. The charge on the inner shell is 3.50 ✕ 10−8 C and th

Sergio039 [100]

Answer:

The magnitude of the electric field are $2.38\times10^{4}\ N/C$ and $1.09\times10^{4}\ N/C$

Explanation:

Given that,

Radius of inner shell = 11.0 cm

Radius of outer shell = 14.0 cm

Charge on inner shell $q_{inn}=3.50\times10^{-8}\ C$

Charge on outer shell $q_{out}=1.60\times10^{-8}\ C$

Suppose, at r = 11.5 cm and at r = 20.5 cm

We need to calculate the magnitude of the electric field at r = 11.5 cm

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Where, q = charge

k = constant

r = distance

Put the value into the formula

$E=\dfrac{9\times10^{9}\times3.50\times10^{-8}}{(11.5\times10^{-2})^2}$

$E=2.38\times10^{4}\ N/C$

The total charge enclosed by a radial distance 20.5 cm

The total charge is

$q=q_{inn}+q_{out}$

Put the value into the formula

$q=3.50\times10^{-8}+1.60\times10^{-8}$

$q=5.1\times10^{-8}\ C$

We need to calculate the magnitude of the electric field at r = 20.5 cm

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times5.1\times10^{-8}}{(20.5\times10^{-2})^2}$

$E=1.09\times10^{4}\ N/C$

Hence, The magnitude of the electric field are $2.38\times10^{4}\ N/C$ and $1.09\times10^{4}\ N/C$

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3 years ago

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A car travels for 5.5 h at an average speed of 75 km/h. How far did it travel? T TE

ANEK [815]

Answer:

$\boxed {\boxed {\sf 412.5 \ kilometers }}$

Explanation:

Distance is the product of speed and time.

$d=s*t$

The speed of the car is 75 kilometers per hour. It traveled for 5.5 hours.

$s= 75 \ km/hr \\t= 5.5 \ hr$

Substitute the values into the formula.

$d= 75 \ km/hr * 5.5 \ hr$

Multiply. Note that the hours will cancel each other out.

$d= 75 km * 5.5 \\d= 412.5 \ km$

The car travelled 412.5 kilometers.

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3 years ago