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3 years ago

Why are simple everyday actions considered

Physics

2 answers:

Oxana [17]3 years ago

8 0

They create energy ……………….

horsena [70]3 years ago

7 0

Answer:

They transform energy

Explanation:

thermodynamics deals with transfers of energy from one place to another and from one form to another and it's also deal with the relationship between heat and other forms of energy

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A satellite with a mass of 120 kg fires its rocket thrusters, which give an impulse of 7440 kg-m/s. What was the total change in

Marat540 [252]

From the calculation and the momentum of the body, the velocity is 62 m/s

<h3>What is momentum?</h3>

The term momentum refers to the product of mass and velocity. Now recall that the rate of change of momentum is equal to the impressed force.

Hence;

7440 kg-m/s = 120 kg * v

v= 7440 kg-m/s/120 kg

v = 62 m/s

Learn more about momentum:brainly.com/question/24030570

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3 0

2 years ago

When all parts of a circuit are composed of conducting materials, the circuit is said to be

Keith_Richards [23]

When all parts of a circuit are composed of conducting materials,
then it's possible for current to flow in the circuit, and we say that
the circuit is "closed".

5 0

3 years ago

I WILLL GIVE BRAINLYEST!!!

4vir4ik [10]

Answer:

Increasing temperatures evaporate water faster, causing an increase in salinity.

Explanation:

When the water molecules of the ocean become heated, they expand. ... Since warmer water thus can hold more salt and other molecules than cold water; it can have a higher salinity.

3 0

3 years ago

A 31 kg block is initially at rest on a horizontal surface. A horizontal force of 83 N is required to set the block in motion. A

Hatshy [7]

Answer:

The static and kinetic coefficients of friction are 0.273 and 0.181, respectively.

Explanation:

By Newton's Laws of Motion and definition of maximum friction force, we derive the following two formulas for the static and kinetic coefficients of friction:

$\mu_{s} = \frac{f_{s}}{m\cdot g}$ (1)

$\mu_{k} = \frac{f_{k}}{m\cdot g}$ (2)

Where:

$\mu_{s}$ - Static coefficient of friction, no unit.

$\mu_{k}$ - Kinetic coefficient of friction, no unit.

$f_{s}$ - Static friction force, in newtons.

$f_{k}$ - Kinetic friction force, in newtons.

$m$ - Mass, in kilograms.

$g$ - Gravitational constant, in meters per square second.

If we know that $f_{s} = 83\,N$ , $f_{k} = 55\,N$ , $m = 31\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the coefficients of friction are, respectively: