Answer:
The kinetic energy of the bullet is 5.4 × 10³ J
Explanation:
Hi there!
The equation of kinetic energy is the following:
KE = 1/2 · m · v²
Where:
KE = kinetic energy.
m = mass of the bullet.
v = speed of the bullet.
Let´s convert the mass unit to kg so that our result is in Joules:
64 g · ( 1 kg / 1000 g) = 0.064 kg
Then, the kinetic energy will be the following:
KE = 1/2 · 0.064 kg · (411 m/s)²
KE = 5.4 × 10³ J
Answer:
option D
Explanation:
this is because it occurs in many different dimensions, including biological, cognitive and socioemotional. this is also the answer on apex.
To solve this problem we will apply the concepts related to the Magnetic Force, this is given by the product between the current, the body length, the magnetic field and the angle between the force and the magnetic field, mathematically that is,
![F = ILBsin \theta](https://tex.z-dn.net/?f=F%20%3D%20ILBsin%20%5Ctheta)
Here,
I = Current
L = Length
B = Magnetic Field
= Angle between Force and Magnetic Field
But ![\theta = 90\°](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2090%5C%C2%B0)
![F = ILB](https://tex.z-dn.net/?f=F%20%3D%20ILB)
Rearranging to find the Magnetic Field,
![B = \frac{F}{IL}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7BF%7D%7BIL%7D)
Here the force per unit length,
![B = \frac{1}{I}\frac{F}{L}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B1%7D%7BI%7D%5Cfrac%7BF%7D%7BL%7D)
Replacing with our values,
![B = \frac{0.130N/m}{16.5}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B0.130N%2Fm%7D%7B16.5%7D)
![B = 0.0078T](https://tex.z-dn.net/?f=B%20%3D%200.0078T)
Therefore the magnitude of the magnetic field in the region through which the current passes is 0.0078T
Answer:
5.6*10^23. if 10^n is greater, that means its the larger value. hope dis helps
Explanation: