Answer:
The x-component of 
is 56.148 newtons.
Explanation:
From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:
(1)
Where:
, 
, 
- External forces exerted on the ring, measured in newtons.
- Vector zero, measured in newtons.
If we know that ![\vec F_{1} = (70.711,70.711)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20F_%7B1%7D%20%3D%20%2870.711%2C70.711%29%5C%2C%5BN%5D)
, ![\vec F_{2} = (-126.859, 46.173)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20F_%7B2%7D%20%3D%20%28-126.859%2C%2046.173%29%5C%2C%5BN%5D)
, 
and ![\vec O = (0,0)\,[N]](https://tex.z-dn.net/?f=%5Cvec%20O%20%3D%20%280%2C0%29%5C%2C%5BN%5D)
, then we construct the following system of linear equations:
(2)
(3)
The solution of this system is:
, 
The x-component of is 56.148 newtons.
Answer:
True The net force must be zero for the acceleration to be zero
Explanation:
In order to analyze the statements of this problem we propose your solution.
First let's look at Newton's first, which stable that every object is at rest or with constant speed unless something takes it out of this state (acceleration)
Now let's look at the second postulate, which says that force is related to the product of the mass of a body and its acceleration.
As a result of these two laws, for a body is a constant velocity the summation force on it must be zero.
Now we can analyze the statements given.
True The net force must be zero for the acceleration to be zero
False. If the force is different from zero, there is acceleration that changes the speeds
False. There may be forces, but the sum of them must be zero
False. If a force acts, the acceleration is different from zero and the speed changes
No it can't it's material
Answer:
D. sweeper
Explanation:
i did the assignment and got it right
