Question

Worth 25 points on my exam

Answer 1

• Initial velocity=20m/s
• Final velocity=0m/s(As the car stops)
• Acceleration=-8m/s^2
• Distance=s=26m

We need to verify the thrid equation of kinematics here

$\\ \tt\longmapsto v^2-u^2=2as$

$\\ \tt\longmapsto 20^2=2(-8)s$

$\\ \tt\longmapsto 400=-16s$

$\\ \tt\longmapsto s=|400/-16|$

$\\ \tt\longmapsto s=25m$

The squirrel has a good luck ,Car gets stopped just 1m away from the squirrel .

Answer 2

Explanation:

According to the Question

A squirrel runs out in front of a car moving at +20m/s ( initial speed u) . The driver slams on the brakes and begins decreasing at -8m/s² ( here the acceleration is acting in opposite directions of motion a )

When Squirrel was 26 metres ( Distance from the car initially )

Using Kinematic Equation

• v² = u² + 2as

On substituting the value we obtain

➥ 0² = 20² + 2 × -8 × s

➥ 0 = 400 - 16 × s

➥ -400 = -16 × s

➥ 400/16 = s

➥ 25 = s

So, the squirrel is 25 metres from the car .