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3 years ago

What is latitude 20 degrees north and longitude 65 degrees west?

1 answer:

3 0

<span>The latitude 20 degrees north and longitude 65 degrees west is in the Atlantic Ocean, north of Puerto. The north coast region of Puerto Rico named "Porta Atlantico" faces the dark blue Atlantic Ocean. On the off chance that you long for unwinding on a tranquil shoreline, losing all sense of direction in the magnificence of waves smashing, and being calmed by their song, you might need to remain on the north drift, lease an auto and investigate.</span>

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A certain gas occupies a volume of 3.7 L at a pressure of 0.91 atm and a temperature of 283 K. It is compressed adiabatically to

Nostrana [21]

Answer:

(a)

P₂ = 7.13 atm

(b)

T₂ = 157.14 K

Explanation:

(a)

V₁ = initial volume = 3.7 L = 3.7 x 10⁻³ m³

V₂ = final volume = 0.85 L = 0.85 x 10⁻³ m³

P₁ = Initial Pressure of the gas = 0.91 atm = 0.91 x 101325 = 92205.75 Pa

P₂ = Final Pressure of the gas = ?

Using the equation

$P_{1} V{_{1}}^{\gamma } = P_{2} V{_{2}}^{\gamma }$

$(92205.75) (3.7\times 10^{-3})^{1.4 } = P_{2} (0.85\times 10^{-3})^{1.4 }$

$P_{2}$ = 722860 Pa

$P_{2}$ = 7.13 atm

(b)

T₁ = initial temperature =283 K

T₂ = Final temperature = ?

using the equation

$P{_{1}}^{1-\gamma } T{_{1}}^{\gamma } = P{_{2}}^{1-\gamma } T{_{2}}^{\gamma }$

$(92205.75)^{1-1.4 } (283)^{1.4 } = (722860)^{1-1.4 } T{_{2}}^{1.4 }$

T₂ = 157.14 K

6 0

2 years ago

a bicyclist travels with an averahe velocity of 15km/h north, for 20 minutes .what is his displacement ?

Lunna [17]

Explanation:

velocity = 15 km/hr = 15×1000m / 60×60s

= 4.17 m/s

time= 20 min= 20 × 60s

= 1200s

displacement =?

we know that,

V = D / t

or, 4.17 = D / 1200

or, D = 4.17 × 1200

or,D = 5004 m

7 0

2 years ago

If a material were being designed to demonstrate no thermal expansions, how would the energy plot look like?

bixtya [17]

The characteristics of thermal expansion allow finding that the response for a material without thermal expansion is

The length variation is zero

In the graph the line is horizontal so there is no change in length with temperature

Thermal expansion is the macroscopic sum of the changes in the length of the bonds when the energy (temperature) changes, it can be written

ΔL = α L₀ ΔT

Where ΔL is the change in length, α the coefficient of linear expansion, L₀ the initial length and ΔT the change in body temperature

In this case, a material is being designed that the thermal expansion is very small, for this the material must be made up of several compounds where some of them present a contraction with temperature, some examples: water at low temperature, liquefied gases , ceramic tile, quartz, etc.

The thermal expansion measurement processes control the body temperature and measure the change in length, in this case the change in length must be zero, in the attachment we can see a graph of a composite material with these characteristics, an example of this type of material is Invar an alloy of nickel and iron α = 3.7 10⁻⁶ ºC⁻¹

In conclusion, using the characteristics of thermal expansion we can find that the response of material without thermal expansion is

The length variation is zero

In the graph the line is horizontal so there is no change in length with temperature

Learn more here: brainly.com/question/18717902

5 0

2 years ago

A 3000-kg crane is supporting a 10,000-kg crate. The crane pivots about point A and is at rest pressed against a support at B. (

Maru [420]

The answers are physically and mathematically reasonable, since both have the <em>same</em> order of magnitude of the <em>external</em> forces shown in the figure.

<h3 /><h3>Procedure - Determination of forces acting on a rigid body</h3>

Let be a system at equilibrium, which mathematically is represented by the following formulas:

$\Sigma F = 0$ (1)

$\Sigma M = 0$ (2)

<h3>a) Force acting on the crane at point A</h3>

We construct equations around points A and B by Newton's Laws and D'Alembert Principle:

<h3>Point A</h3>

$\Sigma M = F_{B}\cdot (1\,m)-(3000\,kgf)\cdot (2\,m)-(10000\,kgf)\cdot (6\,m) = 0$ (3)

<h3 /><h3>Point B</h3>

$\Sigma M = -F_{A,x}\cdot (1\,m) - (3000\,kgf)\cdot (2\,m)-(10000\,kgf)\cdot (6\,m) = 0$ (4)

<h3 /><h3>Entire system</h3>

$\Sigma F_{x} = F_{A,x} + F_{B} = 0$ (5)

$\Sigma F_{y} = F_{A,y} -3000\,kgf-10000\,kgf = 0$ (6)

The solution of the <em>entire</em> system is: $F_{A,x} = -66000\,kgf$ , $F_{B} = 66000\,kgf$ and $F_{A,y} = 13000\,kgf$ .

The magnitude of the force acting on the crane at point A is determined by the Pythagorean theorem:

$F_{A} = \sqrt{(-66000\,kgf)^{2}+(13000\,kgf)^{2}}$

$F_{A} \approx 67268.120\,kgf$

The force acting on the crane at point A has a magnitude of approximately 67268.128 kilograms-force. $\blacksquare$

<h3>b) The force acting on the crane at point B</h3>

The force acting on the crane at point B has a magnitude of approximately 66000 kilograms-force. $\blacksquare$

<h3>c) Order of Magnitude sense-making</h3>

The answers of parts (a) and (b) have an order of magnitude of $10^{3}$ , the same order of magnitude of the external forces shown in the figure. Hence, those answers are physically and mathematically reasonable.

<h3>Remark</h3>

Figure is missing. The statement is incomplete. Complete statement is presented below:

<em>A 3000 kilograms-force is supporting a 10000 kilograms-force crate. The crane pivots about point A and is at rest pressed against a support at B. </em>

<em>(a)</em><em> FInd the force acting on the crane at point A. </em>

<em>(b)</em><em> Find the force acting on the crane at point B. </em>

<em>(c)</em><em> Use order of magnitude sense-making to determine the reasonableness of your answers to parts (a) and (b). Hint: consider how the lever arm to the crate is much different than that to other points. </em>

To learn more on rigid bodies, we kindly invite to check this verified question: brainly.com/question/7031958

7 0

2 years ago

Suppose the sun were to suddenly shrink in size but its mass remained the same. according to the law of conservation of angular

Ronch [10]

Since the angular momentum is conserved, and the moment of inertia has decreased, so the angular velocity of the sun will rapidly increase and the sun will spin faster

8 0

3 years ago