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andreyandreev [35.5K]
3 years ago
14

H A and H B are both weak acids in water, and HA is a stronger acid than HB. Which of the following statements is correct? Selec

t one: a. B is a stronger base than A^-, which is a stronger base than H_2O, which is a stronger base than CI^-. b. B is a stronger base than A^-, which is a stronger base than CI^-, which is a stronger base than H_2O. c. None of these (A-D) is correct. d. CI^- is a stronger base than A^-, which is a stronger base than B^-, which is a stronger base than H_2O e. A^- is a stronger base than B^-, which is a stronger base than H_2O, which is a stronger base than CI^-
Chemistry
1 answer:
lubasha [3.4K]3 years ago
4 0

Answer:

B is a stronger base than A^-, which is a stronger base than H2O, which is a stronger base than CI^-

Explanation:

The general equation for each acid is:

HA(aq) + H2O(ac) ⇄ H3O+(aq) + A-(aq)

HB(aq) + H2O(ac) ⇄ H3O+(aq) + B-(aq)

When these acids dissociate into its ions in water they lose a proton (H+), so they are proton donors (acids) and H2O is the proton acceptor (base). This reaction produces a conjugate acid and a conjugate base.

Conjugate base is what remains of the acid molecule after it loses a proton:

HA = acid         A- Conjugate base

HB = acid         B- Conjugate base

A conjugate acid is formed when the proton is transferred to the base

H2O = base                H3O+ = Conjugate acid

The stronger acid will produce a weaker base. According to this, if HA is a stronger acid than HB, A- would be the weaker base (B- is the stronger base).

Compared with water, A- and B- are stronger bases because when they compete for a proton they have much greater affinity for H+ than water does and the equilibrium position will lie far to the left. (HA and HB are weak acids)

Finally Cl- is the weakest base because it comes after dissociation of HCl which is a strong acid

HCl(aq) + H2O → H3O+(aq) + Cl-(aq)

Note there is no double arrows, equilibrium lies far to the right. A strong acid yields a weak conjugate base it means one that has a low affinity for a proton.

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<span>If you give it a good search, the most used answer would probably be as follows,

</span><span>In 1914 Henry Moseley found a relationship between an element's X-ray wavelength and its atomic number (Z), and therefore rearranged the table by nuclear charge / atomic number rather than atomic weight. Before this discovery, atomic numbers were just sequential numbers based on an element's atomic weight. Moseley's discovery showed that atomic numbers had an experimentally measurable basis.
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5 0
3 years ago
Read 2 more answers
Write the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by each:
Maru [420]

Answer :

(a) The charge and full ground-state electron configuration of the monatomic ion is, (+1) and 1s^22s^22p^63s^23p^64s^23d^{10}4p^6

(b) The charge and full ground-state electron configuration of the monatomic ion is, (-3) and 1s^22s^22p^6

(c) The charge and full ground-state electron configuration of the monatomic ion is, (-1) and 1s^22s^22p^63s^23p^64s^23d^{10}4p^6

Explanation :

For the neutral atom, the number of protons and electrons are equal. But, they are unequal when the atoms present in the form of ions or the atom has some charges.

When an unequal number of electrons and protons then it leads to the formation of ionic species.

Ion : An ion is formed when an atom looses or gains electron.

When an atom looses electrons, it will form a positive ion known as cation.

When an atom gains electrons, it will form a negative ion known as anion.

(a) The given element is, Rb (Rubidium)

As we know that the rubidium element belongs to group 1 and the atomic number is, 37

The ground-state electron configuration of Rb is:

1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1

This element will easily loose 1 electron and form Rb^+ ion  which attain stable noble gas electronic configuration.

The full ground-state electron configuration of Rb ion is:

1s^22s^22p^63s^23p^64s^23d^{10}4p^6

(b) The given element is, N (Nitrogen)

As we know that the nitrogen element belongs to group 15 and the atomic number is, 7

The ground-state electron configuration of N is:

1s^22s^22p^3

This element will easily gain 3 electrons and form N^{3-} ion  which attain stable noble gas electronic configuration.

The full ground-state electron configuration of N ion is:

1s^22s^22p^6

(c) The given element is, Br (Bromine)

As we know that the bromine element belongs to group 17 and the atomic number is, 35

The ground-state electron configuration of Rb is:

1s^22s^22p^63s^23p^64s^23d^{10}4p^5

This element will easily gain 1 electron and form Br^- ion  which attain stable noble gas electronic configuration.

The full ground-state electron configuration of Br ion is:

1s^22s^22p^63s^23p^64s^23d^{10}4p^6

4 0
3 years ago
What is the molarity of a 17.0% by mass solution of sodium acetate, NaC2H3O2 (82.0 g/mol), in water? The density of the solution
sattari [20]

Answer:

[NaCH₃COO] = 2.26M

Explanation:

17% by mass is a sort of concentration. Gives the information about grams of solute in 100 g of solution. (In this case, 17 g of NaCH₃COO)

Let's determine the volume of solution, by density

Mass of solution / Volume of solution = Solution density

100 g / Volume of solution = 1.09 g/mL

100 g / 1.09 g/mL = 91.7 mL

17 grams of solute is contained in 91.7 mL

Molarity (M) = Mol of solute /L of solution

91.7 mL / 1000 = 0.0917L

17 g / 82 g/m = 0.207 moles

Molariy = 0.207 moles / 0.0917L → 2.26M

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Accuracy vs. Precision
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Accuracy is the closeness to the specific target and precision is the closeness of the measurements to each other.

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Answer:

See explanation

Explanation:

The IUPAC name of aspirin is 2-Acetoxybenzoic acid. It is composed of an acetoxy moiety and a benzoic acid moiety.

The compound can be hydrolysed under prolonged storage conditions to yield acetic acid which causes the vinegar like odour.

Also, one of the products of this hydrolysis bears a phenol group which reacts with FeCl3 to give a purple color.

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3 years ago
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