The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/
.
Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.
To determine Paola's acceleration, the third equation of free fall is appropriate.
i.e 
= 
± 2as
where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.
From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.
So that since Poala flies against gravity, then we have:
= - 2as
0 = 
- 2(a x 0.201)
= 16 - 0.402a
0.402a = 16
a = 
= 39.801
a = 39.80 m/
Therefore Paola's acceleration is 39.80 m/.
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<em>A</em> - <em>B</em> = (10<em>i</em> - 2<em>j</em> - 4<em>k</em>) - (<em>i</em> + 7<em>j</em> - <em>k</em>)
<em>A</em> - <em>B</em> = 9<em>i</em> - 9<em>j</em> - 3<em>k</em>
|<em>A</em> - <em>B</em>| = √(9² + (-9)² + (-3)²) = √189 = 3√19
Folds and faults are difficult to identify because they occur in the interior of rocks and also due to the dense nature of the materials.
<h3>What are faults and folds?</h3>
Faults are lines of weakness are present in materials dues to uneven positioning of the particles of the material.
Folds occurs when infolds occur in materials.
Faults and folds usually occur in rocks.
Folds and faults are difficult to identify because they occur internally and also due to the dense nature of the materials.
Learn more about faults and folds at: brainly.com/question/14240712
Using the equation E = hc/λ we can find out how much energy a single photon of wavelength 193 nm has. E = Planck Constant * Speed of Light/193 nm
