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alisha [4.7K]
3 years ago
7

What causes Seafloor spreading

Physics
2 answers:
Rasek [7]3 years ago
5 0
Sea floor spreading is caused by the continual injection of magma from the sea bed in between ridges found in mid-ocean. Injection of magma causes formation of new sea floor. Forces cause the sea floor on each side of the mid-ocean ridge to move in opposite directions, each side belonging to a different lithospheric plate. This process is continuous and results in an ever widening (spreading) sea floor at the expense of area lost elsewhere on the planet. Seafloor spreading ends when mid ocean ridges are subducted.
valentina_108 [34]3 years ago
4 0

Answer:

A. magma from convection currents

Explanation:

I took the test

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An octopus propels itself through the water by ejecting water through a funnel in its body. How does this demonstrate Newton’s t
valina [46]

Answer: The answer would be C. When Octopus eject the water out, the water acts with an equal force on the octopus in opposite direction.

Explanation:

An octopus propels itself forward in the water by ejecting water backward through a funnel in its body.

Hope this helps! :D

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3 years ago
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44.2 cm + 0.123 cm = cm
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it's nighttime, and you've dropped your goggles into a swimming pool that is 3.2 m deep. If you hold a laser pointer 1.0 m above
Scrat [10]

Answer:

5.2 m

Explanation:

from the question we are given the following

depth of pool (d) = 3.2 m

height of laser above the pool (h) = 1 m

point of entry of laser beam from edge of water (l) = 2.5 m

we first have to calculate the angle at which the laser beam enters the water (∝),

tan ∝ = \frac{1}{2.2}

∝ = 24.44 degrees

from the attached diagram, the angle with the normal (i) = 90 - 24.4 = 65.56 degrees

lets assume it is a red laser which has a refractive index of 1.331 in water, and with this we can find the angle of refraction (r) using the formula below

refractive index = \frac{sin i}{sin r}

1.331 = \frac{sin 65.56}{sin r}

r = 43.16 degrees

we can get the distance (x) from tan r = \frac{x}{3.2}

tan 43.16 = \frac{x}{3.2}

x = 3 m

To get the total distance we need to add the value of x to 2.2 m

total distance = 3 + 2.2 = 5.2 m

3 0
3 years ago
A circuit contains a 1.5v battery and a bulb with a 3 ohms resistance, calculate the current of the circuit
alexandr1967 [171]

Answer: 0.5ampere

Explanation:V=IR

Where v=voltage

I=current and

R= resistance

Therefore, I=V/R = 1.5/3

= 0.5ampere

5 0
4 years ago
The angular speed of an automobile engine is increased at a constant rate from 1120 rev/min to 2560 rev/min in 13.8 s. (a) What
Neko [114]

Complete Question

The angular speed of an automobile engine is increased at a constant rate from 1120 rev/min to 2560 rev/min in 13.8 s.

(a) What is its angular acceleration in revolutions per minute-squared

(b) How many revolutions does the engine make during this 20 s interval?

rev

Answer:

a

 \alpha = 6261 \  rev/minutes^2

b

 \theta  = 613 \ revolutions

Explanation:

From the question we are told that

   The initial  angular speed is w_i =  1120 \ rev/minutes

    The angular speed after t = 13.8 s = \frac{13.8}{60 }  = 0.23 \ minutes  is w_f = 2560 \ rev/minutes

    The time for revolution considered is t_r =  20 \ s  =  \frac{20}{60} = 0.333 \  minutes  

 Generally the angular acceleration is mathematically represented as

         \alpha = \frac{w_f - w_i }{t}

=>      \alpha = \frac{2560  - 1120 }{0.23}  

=>      \alpha = 6261 \  rev/minutes^2

Generally the number of revolution made is t_r =  20 \ s  =  \frac{20}{60} = 0.333 \  minutes  is mathematically represented as

           \theta  =  \frac{1}{2}  * (w_i + w_f)*  t

=>      \theta  =  \frac{1}{2}  * (1120+ 2560 )*  0.333

=>      \theta  = 613 \ revolutions

5 0
3 years ago
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