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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics

2 answers:

taurus [48]3 years ago

7 0

the answer to the potential energy of the baby and stroller is 1960 J

Alekssandra [29.7K]3 years ago

3 0

so, question number 10 answer is 82 watts

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An alternative to CFL bulbs and incandescent bulbs are light-emitting diode (LED) bulbs. A 16-W LED bulb can replace a 100-W inc

Yanka [14]

Answer:

LED bulb = 0.145 A

Incandescent bulb = 0.909 A

CFL bulb = 0.218 A

Explanation:

Given:

Power rating of LED bulb (P₁) = 16 W

Power rating of incandescent bulb (P₂) = 100 W

Power rating of CFL bulb (P₃) = 24 W

Terminal voltage across the circuit (V) = 110 V

We know that, power is related to terminal voltage and current drawn as:

$P=VI$

Express this in terms of 'I'. This gives,

$I=\frac{P}{V}$

Now, calculate the current drawn in each bulb using their respective values.

For LED bulb, $P_1=16\ W, V=110\ V$

So, current drawn is given as:

$I_1=\frac{16\ W}{110\ V}=0.145\ A$

For incandescent bulb, $P_2=100\ W, V=110\ V$

So, current drawn is given as:

$I_2=\frac{100\ W}{110\ V}=0.909\ A$

For CFL bulb, $P_3=24\ W, V=110\ V$

So, current drawn is given as:

$I_3=\frac{24\ W}{110\ V}=0.218\ A$

Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.

5 0

3 years ago

A ball of mass 8 kg falls from rest from a height of 100 m. Neglecting air resistance,calculate its kinetic energy after falling

astra-53 [7]

As an object falls from rest, its gravitational energy is converted to kinetic energy

G.P.E = K.E = mgh

K.E = (80 Kg)(9.8 m/s²)(30 m)

K.E. = 23,520 J

4 0

3 years ago

Read 2 more answers

What does it mean for a chemical equation to be balanced?

kolezko [41]

Answer:

<h2>The number of each type of atom is the same for both the reactants and products.</h2>

I hope this helps

3 0

3 years ago

The electric field at the surface of a charged, solid, copper sphere with radius 0.220 mm is 4200 N/CN/C, directed toward the ce

NISA [10]

Answer:

The potential at the center of the sphere is -924 V

Explanation:

Given;

radius of the sphere, R = 0.22 m

electric field at the surface of the sphere, E = 4200 N/C

Since the electric field is directed towards the center of the sphere, the charge is negative.

The Potential is the same at every point in the sphere, and it is given as;

$V = \frac{1}{4 \pi \epsilon_o} \frac{q}{R}$ -------equation (1)

The electric field on the sphere is also given as;

$E = \frac{1}{4 \pi \epsilon _o} \frac{|q|}{R^2}$

$|q |= 4 \pi \epsilon _o} R^2E$

Substitute in the value of q in equation (1)

$V = \frac{1}{4 \pi \epsilon_o} \frac{-(4 \pi \epsilon _o R^2E)}{R} \ \ \ \ q \ is \ negative\ because \ E \ is\ directed \ toward \ the \ center\\\\V = -RE\\\\V = -(0.22* 4200)\\\\V = -924 \ V$

Therefore, the potential at the center of the sphere is -924 V

8 0

3 years ago

I'LL MARK BRAINLIEST PLZ HELP MEH I NEED IT RN I'LL BE YOUR FRIEND TOO *sniff*

algol13

Lets say a plant native to greenland is in canada (fossilized against canada's shore line) it's proof that at one moment they where actually connecting. <3

4 0

2 years ago

Read 2 more answers