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OlgaM077 [116]
3 years ago
7

if a ball on a string swung in a circles and string suddenly breaks.the ball will move into what direction?

Physics
1 answer:
horrorfan [7]3 years ago
8 0

Answer:

The ball will swing in the direction it was going once the string breaks.

Explanation:

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A 4-kilogram ball moving at 8 m/sec to the right collides with a 1-kilogram ball at rest. After the collision,
elena-14-01-66 [18.8K]
Conservation of momentum: total momentum before = total momentum after

Momentum = mass x velocity

So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32

Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32

Therefore β = 12.8 m/s
4 0
3 years ago
One student made the incomplete diagram shown below to represent the relationship between igneous rocks, sediments, sedimentary
Kryger [21]

Answer: Option (C)

Explanation: Rock cycle plays an important role in the alteration of rocks from one form to another.

  1. Igneous rocks when undergoes high temperature and pressure condition, it transforms into a metamorphic rock.
  2. Sedimentary rocks are formed from the sedimentation and consolidation of sediments
  3. Igneous rocks are formed due to the crystallization of magma.

Hence the correct answer is option (C)

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3 years ago
An object is represented by the dot on the motion map. Which object is most likely represented by the dot?
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B) I just took the test and put D but it gave me the wrong answer. It told me it was B.

5 0
3 years ago
Read 2 more answers
Daily life examples of pressure of solids on solids?​
Ipatiy [6.2K]

Explanation:

There's a massive amount, just think of anything everyday. Like a table on the floor, or when your walking around and putting pressure on the floor. When you squeeze something which is solid. Anything like that will do.

6 0
3 years ago
The blades in a blender rotate at a rate of 6100 rpm. When the motor is turned off during operation, the blades slow to rest in
MissTica

Answer:

<em>155.80rad/s</em>

Explanation:

Using the equation of motion to find the angular acceleration:

\omega_f = \omega_i + \alpha t

\omega_f is the final angular velocity in rad/s

\omega_i  is the initial angular velocity in rad/s

\alpha is the angular acceleration

t is the time taken

Given the following

\omega_f = 6100rpm

Time = 4.1secs

Convert the angular velocity to rad/s

1rpm = 0.10472rad/s

6100rpm = x

x = 6100 * 0.10472

x  = 638.792rad/s

\omega_f = 638.792rad/s\\

Get the angular acceleration:

Recall that:

\omega_f = \omega_i + \alpha t

638.792 = 0 + ∝(4.1)

4.1∝ = 638.792

∝ = 638.792/4.1

∝ = 155.80rad/s

<em>Hence the angular acceleration as the blades slow down is 155.80rad/s</em>

5 0
2 years ago
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