Answer:
The spring constant = 104.82 N/m
The angular velocity of the bar when θ = 32° is 1.70 rad/s
Explanation:
From the diagram attached below; we use the conservation of energy to determine the spring constant by using to formula:
Also;
Thus;
where;
= deflection in the spring
k = spring constant
b = remaining length in the rod
m = mass of the slender bar
g = acceleration due to gravity
Thus; the spring constant = 104.82 N/m
b
The angular velocity can be calculated by also using the conservation of energy;
Thus, the angular velocity of the bar when θ = 32° is 1.70 rad/s
Answer:
True
Explanation:
i searched it up and well this thing is making me do it up till 20 characters long so yea
Answer:
33.6 m
Explanation:
Given:
v₀ = 0 m/s
a = 47.41 m/s²
t = 1.19 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (1.19 s) + ½ (47.41 m/s²) (1.19 s)²
Δx = 33.6 m
Here in this type of question we can use momentum conservation
It is because we can see there is no external force on the system
So we can use momentum conservation principle
here we know that
now after bird sits on it then final speed of the both will be same
so final speed will be 1 m/s
Answer:
The magnitud of the velocity is
and the direccion:
degrees from the horizontal.
Explanation:
Fist we define our variables:
The letters i and j represent the direction of the movement, i in this case is the horizontal direction, and j is perpendicular to i.
velocities with sub-index 1 are the speeds before the crash, and with sub-index 2 are the velocities after the crash.
Using conservation of momentum:
Clearing for the velocity of the stone after the crash:
Substituting known values:
The magnitud of the velocity is :
and the direction:
this is -28.3 degrees from the +i direction or the horizontal direcction.
Note: i and j can also be seen as x and y axis.
