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3 years ago

A train increases its speed steadily from 10 m/s to 20 m/s in

Physics

1 answer:

rewona [7]3 years ago

3 0

Answer:

15m/s

Explanation:

add the two speeds and divide by 2

10+20=30

30/2=15

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The layer of Earth that we live on

fiasKO [112]

We live on the troposphere

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3 years ago

A balloon having an initial temperature of 17.8Â°C is heated so that the volume doubles while the pressure is kept fixed. What i

Rama09 [41]

Answer:

$T = 308.6 ^0 C$

Explanation:

Here by ideal gas equation we can say

$PV = nRT$

now we know that pressure is kept constant here

so we will have

$V = \frac{nR}{P} T$

since we know that number of moles and pressure is constant here

so we have

$\frac{V_2}{V_1} = \frac{T_2}{T_1}$

now we know that initial temperature is 17.8 degree C

and finally volume is doubled

So we have

$\frac{2V}{V} = \frac{T_2}{(273 + 17.8)}$

so final temperature will be

$T_2 = 581.6 k$

$T_2 = 308.6 ^o C$

5 0

3 years ago

What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of −25.0 nc? g?

Daniel [21]

To calculate the force between two negative charges, we use the formula which is given by the Coulomb`s Law as

$F=\frac{kq_{1}q_{2} }{r^{2} }$

Here, $q_{1}$ and $q_{2}$ are the charges on the pith balls, r is the separation between the charges and k is constant and its value is $8.99\times 10^9 N m^2/C^2$ .

Given $q_{1} =q_{2} =-25 nC=-25\times 10^{-9}C$ and $r=8 cm=8\times10^{-2} m$ .

Substituting these values in above formula we get,

$F= 8.99\times 10^9 N m^2/C^2\frac{(-25\times 10^{-9}C)(-25\times 10^{-9}C)}{(8\times10^{-2} m)^2} \\\\\ F= 877929.7\times 10^{-9} N\\\\F=8.8\times10^{-4}N$