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KonstantinChe [14]

2 years ago

6

The plasma membrane of a neuron has voltage-gated sodium and potassium channels. What is the effect of membrane depolarization o

n these channels?.

1 answer:

horsena [70]2 years ago

4 0

Answer:

Depolarization causes the Voltage-gated channels to open in order for ions to flow or rush in

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Can anybody help me please?

vovangra [49]

Answer:

1,2,5

Explanation:

7 0

2 years ago

A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ ௠at a d

Angelina_Jolie [31]

A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ ௠at a distance R from the source. What is the amplitude of the magnetic field at a point 2R from the source?

If the distance from the source is doubled. The amplitude of the magnetic field is smaller 4 times.

4 0

3 years ago

A charged particle accelerated to a velocity v enters the chamber of a mass spectrometer. The particle's velocity is perpendicul

gladu [14]

Answer:

Circle

Explanation:

When a charged particle is in motion in a region with magnetic field, the particle experiences a force whose magnitude is given by

$F=qvB sin \theta$

where

q is the charge

v is the velocity of the particle

B is the strength of the magnetic field

$\theta$ is the angle between the directions of v and B

In this problem, the velocity of the particle is perpendicular to the magnetic field, so

$\theta=90^{\circ}$

and the formula reduces to

$F=qvB$

Also, the direction of this force is perpendicular to the direction of motion of the particle. This means that as the charge moves in the region of the magnetic field, the force acting on it acts as a centripetal force: therefore, the particle will start moving by unifom circular motion, with constant speed (because the magnetic force does no work on the particle, since it is perpendicular to the direction of motion).

So, the path of the particle will be a circle.

4 0

3 years ago

As a diligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.01 m l

Valentin [98]

Answer:

The strength of the magnetic field is $75.6\ \mu T$ .

Explanation:

Given that,

Length of the rod, L = 1.01 m

Speed with which the rod is moving, v = 3.47 m/s

We need to find the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.265 mV across the rod. When the rod is moving with some speed, an emf gets induced and it is given by :

$\epsilon=Blv$

B is magnetic field

$B=\dfrac{\epsilon}{lv}\\\\B=\dfrac{0.265\times 10^{-3}}{1.01\times 3.47}\\\\B=75.6\ \mu T$

So, the strength of the magnetic field is $75.6\ \mu T$ .

6 0

3 years ago

Two students are running down the hallway towards each other. Student 1 has a mass of 107kg and is running to the right at 4.1m/

antiseptic1488 [7]

Answer:

Hi

Explanation:

You are awesome

3 0

2 years ago