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stellarik [79]
2 years ago
15

If a Ferrari, with an initial velocity of 10 m/s, accelerates at a rate of 50 m/s 2 for 3 seconds, what will its final velocity

be? Use the following formula:
Variable
Equation
Solve

Physics
2 answers:
Evgen [1.6K]2 years ago
3 0

Answer:

160m/s

Explanation:

The Ferrari is moving by uniformly accelerated motion, with constant acceleration of a = 50 m/s^2, and initial velocity u = 10 m/s. The velocity at time t of the car is given by

v(t)=u+at

where

u = 10 m/s

a = 50 m/s^2

If we substitute t = 3 s into the equation, we can find the velocity of the car after 3 seconds:

v(3s) = 10m/s + (50m/s^2)(3s)=160m/s

ValentinkaMS [17]2 years ago
3 0

Answer:

160m/s

Explanation:

<em>Rearrange</em><em> the formula:</em>

acceleration = vf - vi ÷ time

acceleration × time = vf - vi

(acceleration × time) + vi = vf

<em>The values are:</em>

acceleration = 50m/s²

time = 3s

vi = 10 m/s

<em>Substitute the values into the formula</em>

(50 × 3) + 10 = 160m/s

The final velocity = 160m/s

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2 years ago
A tennis ball of mass 0.060 kg travels horizontally at a speed of 25m/s. The ball hits a tennis
stepladder [879]
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A motorcycle is speeding along at a velocity of120kph.Then, it changes to a velocity of 150 kph for 2 minutes.What is the motorc
Taya2010 [7]

Answer:

Explanation:

a=v-u/t

a=acceleration

v=final velocity

u=initial velocity

t=tme taken

we need to convert from kph to ms⁻¹

v= 150*1000/60*60= 41.67ms⁻¹

u= 120*1000/60*60= 33.33ms⁻¹

t= 2*60= 120s

a=41.67-33.33/120

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8 0
2 years ago
What net force would be necessary to cause a block of wood with a mass of 2.5 kg to accelerate at a rate of 3.0 m/s2
charle [14.2K]

Answer:

<h2>7.5 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 2.5 kg

acceleration = 3.0 m/s²

We have

force = 2.5 × 3.0 = 7.5

We have the final answer as

<h3>7.5 N</h3>

Hope this helps you

3 0
2 years ago
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
3 years ago
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