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stellarik [79]
3 years ago
15

If a Ferrari, with an initial velocity of 10 m/s, accelerates at a rate of 50 m/s 2 for 3 seconds, what will its final velocity

be? Use the following formula:
Variable
Equation
Solve

Physics
2 answers:
Evgen [1.6K]3 years ago
3 0

Answer:

160m/s

Explanation:

The Ferrari is moving by uniformly accelerated motion, with constant acceleration of a = 50 m/s^2, and initial velocity u = 10 m/s. The velocity at time t of the car is given by

v(t)=u+at

where

u = 10 m/s

a = 50 m/s^2

If we substitute t = 3 s into the equation, we can find the velocity of the car after 3 seconds:

v(3s) = 10m/s + (50m/s^2)(3s)=160m/s

ValentinkaMS [17]3 years ago
3 0

Answer:

160m/s

Explanation:

<em>Rearrange</em><em> the formula:</em>

acceleration = vf - vi ÷ time

acceleration × time = vf - vi

(acceleration × time) + vi = vf

<em>The values are:</em>

acceleration = 50m/s²

time = 3s

vi = 10 m/s

<em>Substitute the values into the formula</em>

(50 × 3) + 10 = 160m/s

The final velocity = 160m/s

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Answer:

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Explanation:

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The minimum speed can be determined by;

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If the appropriate values of the variables are substituted into the expression, the value of the minimum speed required can be determined.

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mamaluj [8]

Answer: a) The acceletarion is directed to the center on the turntable. b) 5 cm; ac= 0.59 m/s^2; 10 cm, ac=1.20 m/s^2; 14 cm, ac=1.66 m/s^2

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ac=ω^2*r where ω and r are the angular speed and teh radios of the circular movement.

w=2*π*f

We know that the turntable is set to 33  1/3 rev/m so

the frequency 33.33/60=0.55 Hz

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r= 0.05 m  ac=3.45^2*0.05=0.50 m/s^2

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