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SVEN [57.7K]
3 years ago
7

Is it right? correct me if im wrong

Physics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

i think it is right

Explanation:

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You pull straight up on the string of a yo-yo with a force 0.24 N, and while your hand is moving up a distance 0.17 m, the yo-yo
Alex

Answer:

The transnational kinetic energy of the yo-yo is 0.083 J.

Explanation:

Given that,

Force=0.24 N

Distance in up= 0.17 m

Distance in down = 0.26 m

Mass of yo-yo = 0.057 kg

Initial speed = 2.4 m/s

Suppose we find the increase in the transnational kinetic energy of the yo-yo

The transnational kinetic energy is equal to the change in potential energy.

We need to calculate the transnational kinetic energy of the yo-yo

Using conservation of energy

\Delta K.E=(mg-F)h

Where, F = force

h = height

m = mass of yo-yo

Put the value into the formula

\Delta K.E=(0.057\times9.8-0.24)\times0.26

\Delta K.E=0.083\ J

Hence, The transnational kinetic energy of the yo-yo is 0.083 J.

3 0
3 years ago
Constanza is on a commuter train between Richville and Shoptown. The train takes 35 minutes to cover the distance between the tw
just olya [345]

Answer:

1.) Displacement = 32.08m

2.) Velocity = 55km/h

3.) Acceleration = 94.29 km/h^2

Explanation:

Given that the train takes 35 minutes to cover the distance between the two towns. The train's average speed is 55 kilometers per hour. That is,

Time t = 35 minute

Convert it to hours by dividing it by 60

35/60 = 7/12 hours

Speed = 55 km/h

The displacement of the car is:

Displacement = 55 × 7/12 = 32.08 m

The velocity of the car will be 55 km/h

The acceleration of the car will be:

Acceleration = velocity/time

Substitute velocity and time into the formula

Acceleration = 55 ÷ 7/12

Acceleration = 94.29 km/h^2

5 0
4 years ago
The velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in
pochemuha

Since g is constant,  the force the escaping gas exerts on the rocket will be 10.4 N

<h3>What is Escape Velocity ?</h3>

This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.

Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.

To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters

  • Mass (m) of the rocket 0.25 Kg
  • Initial velocity u = 15 m/s
  • Final Velocity v = 40 m/s
  • Time t = 0.6s
  • Gravitational field intensity g = 9.8N/kg

The force the gas exerts of the rocket = The force on the rocket

The rate change in momentum of the rocket = force applied

F = ma

F = m(v - u)/t

F = 0.25 x (40 - 15)/0.6

F = 0.25 x 41.667

F = 10.42 N

Since g is constant,  the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.

Learn more about Escape Velocity here: brainly.com/question/13726115

#SPJ1

7 0
2 years ago
Assume a beam with stirrups inclined at 60o angle with respect to the longitudinal steel resisting cracks developing at 45o angl
arlik [135]

Answer:

Shear resistance of a inclined stirrup is given by  

 Vᵇ = Asb(0.95*Fy)(cos α - sin α*cotβ) ((d-d')/sᵇ)

Explanation:

The shear resistance is checked in accordance with BS8110: Part 1, section 3.5.5. Shear resistance of a inclined stirrup is given by  

 Vᵇ = Asb(0.95*Fy)(cos α - sin α*cotβ) ((d-d')/sᵇ)

where,

 Vᵇ=design shear resistance of inclined bars

Asb=cros-sectional area of the inclined bars

Fy=characteristics strength of the stirrups

α=angle between the inclined bars and the axis of the beam

β=angle between the compression strut of inclined bars and the axis of the beam

sᵇ=spacing of the inclined bars

d= effective depth   and d'=effective depth minus cover to reinforcement

The shear stress is given by    

v=V/bd  

 where V is the shear force due to ultimate loads. If v is shear stress

5 0
3 years ago
Explain why the air we breathe and solids, such as steel and bronze, are solutions or homogeneous mixtures, just like salt water
svet-max [94.6K]
Because you can't physically see the difference.
3 0
3 years ago
Read 2 more answers
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