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azamat
3 years ago
13

Which phrases describe the atmosphere? Check all that apply.

Physics
1 answer:
vladimir2022 [97]3 years ago
7 0

Answer:

There is no options for this answer

Explanation:

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A ground-fault circuit interrupter shuts down a circuit if it?
alukav5142 [94]
C: if it senses unequal currents
6 0
2 years ago
Which of the following expressions will have units of kg⋅m/s2? Select all that apply, where x is position, v is velocity, m is m
netineya [11]

Answer: m \frac{d}{dt}v_{(t)}

Explanation:

In the image  attached with this answer are shown the given options from which only one is correct.

The correct expression is:

m \frac{d}{dt}v_{(t)}

Because, if we derive velocity v_{t} with respect to time t we will have acceleration a, hence:

m \frac{d}{dt}v_{(t)}=m.a

Where m is the mass with units of kilograms (kg) and a with units of meter per square seconds \frac{m}{s}^{2}, having as a result kg\frac{m}{s}^{2}

The other expressions are incorrect, let’s prove it:

\frac{m}{2} \frac{d}{dx}{(v_{(x)})}^{2}=\frac{m}{2} 2v_{(x)}^{2-1}=mv_{(x)} This result has units of kg\frac{m}{s}

m\frac{d}{dt}a_{(t)}=ma_{(t)}^{1-1}=m This result has units of kg

m\int x_{(t)} dt= m \frac{{(x_{(t)})}^{1+1}}{1+1}+C=m\frac{{(x_{(t)})}^{2}}{2}+C This result has units of kgm^{2} and C is a constant

m\frac{d}{dt}x_{(t)}=mx_{(t)}^{1-1}=m This result has units of kg

m\frac{d}{dt}v_{(t)}=mv_{(t)}^{1-1}=m This result has units of kg

\frac{m}{2}\int {(v_{(t)})}^{2} dt= \frac{m}{2} \frac{{(v_{(t)})}^{2+1}}{2+1}+C=\frac{m}{6} {(v_{(t)})}^{3}+C This result has units of kg \frac{m^{3}}{s^{3}} and C is a constant

m\int a_{(t)} dt= \frac{m {a_{(t)}}^{2}}{2}+C This result has units of kg \frac{m^{2}}{s^{4}} and C is a constant

\frac{m}{2} \frac{d}{dt}{(v_{(x)})}^{2}=0 because v_{(x)} is a constant in this derivation respect to t

m\int v_{(t)} dt= \frac{m {v_{(t)}}^{2}}{2}+C This result has units of kg \frac{m^{2}}{s^{2}} and C is a constant

6 0
3 years ago
Help with 3 and check the other ones please :(
Kobotan [32]

Answer:

number 3 The wind because the wind has strong pressure which causes to change peoples directions in where they are going

Explanation:

hope this helped by the way i think you answered b and 4 i don't know if this is a test and i sent this at the wrong time :(

4 0
3 years ago
Read 2 more answers
A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What
icang [17]

Answer:

Friction between the box and the floor is 25N to the left

Explanation:

There are two forces acting on the box along the horizontal direction:

- The force of push applied by the worker, in the forward direction, F

- The force of friction, F_f, acting in the opposite direction (backward)

So the net force acting on the box is

F_{net}=F-F_f

According to Newton's second law of motion, the net force on an object is equal to the product between its mass (m) and its acceleration (a), so we can write:

F_{net}=ma

And so

F-F_f = ma

However, in this case the box is moving at constant speed; this means that its acceleration is zero:

a=0

Therefore we have:

F-F_f=0

Which means

F_f=F

And since we are told that

F=25 N

This means that the force of friction is also 25 N:

F_f=F=25 N

6 0
4 years ago
Read 2 more answers
A 70-kg ice skater is standing still on the ice, when a friend tosses him a 10-kg ball that is traveling at +8 m/s. If he catche
Misha Larkins [42]

Answer:+1.25 m/s

Explanation:

Given

mass of ice skater M=70 kg

mass of ball m=10 kg

the initial velocity of the ball  u_1=+8\ m/s

Conserving linear momentum

M\times0+m\timesu_1=(M+m)v\quad \quad [v=\text{combined velocity of skater and ball}]

v=\dfrac{10\times10}{80}=+1.25\ m/s

Therefore the velocity of the person holding the ball is 1.25 m/s

This collision represents the perfectly inelastic collision where particles stick together after the collision.

7 0
3 years ago
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