Firstly, to find speed you need to remember the speed formula:
Speed = Distance ÷ Time
You can do it by doing 2800 ÷ 2 but that gives m/h (metres per hour)
So to convert hours into seconds, you multiply 2 by 7200 (amount of second in 2 hours:
2 * 7200 = 14400 seconds
Now we can do distance ÷ time by plugging the values in:
2800 ÷ 14400 = ≈0.194
Answer:
Voltage, V = 0.0524 volts
Explanation:
Thickness of the membrane,
Electric field strength,
We need to find the voltage across it. The relationship between the voltage, electric field and the distance is given by :
V = 0.0524 volts
So, the voltage across the thick membrane is 0.0524 volts. Hence, this is the required solution.
Answer:
Given:
mass of the ball m = 0.144 kg
velocity v = 38 m/s
now, change in momentum
P = m v- ( - mv)
= 2 mv
=2 x (0.144) x (38)
= 10.944 kg-m/s
Impulse J= F. Δt
change in momentum is equal to impulse
J = 10.944 kg-m/s
we know force is equal to change in momentum per unit time
F = 13.68 x 10³ N
F = 13.68 kN
ANSWER:100dB
f<em>rom the sound intensity level,the sound intensity is calculated as:</em>
<em /><em>₁=</em>
<em>=(10dB)㏒₁₀(l₁/l₀)</em>
<em>inserting numbers:</em>
<em>120dB=(10dB)㏒₁₀[l₁/10⁻¹²W/m⁸] or 12=㏒₁₀[l₁/(10⁻¹²)W/m²</em>
<em>Getting the antilog of both sides and obtain 10¹²=l₁(10⁻¹²W/m²)which </em>
<em>can be used to solve for l₁ and get</em>
<em> l₁=(10⁻¹²W/m²)(10¹²)=1 W/m²</em>
<em>since the sound intensity is related to the power and that the power does not change,the sound intensity at any other point can be solved.Plugging-in</em>
<em>ᵃ = 4πr²,into P=l₁ₐ₁=l₂ₐ₂ and get:</em>
<em>l₂=l₁(r₁/r₂)² =(1W/m²)(5/35) =2.04×10⁻²W/m²</em>
<em>since we know the sound intensity at the sound point 2r,the sound intensity level at the point can be solved.We have:</em>
<em> </em><em>₂=</em>
<em>=(10dB)㏒₁₀(l₂/l₀)=(10dB)㏒₁₀(2.04×10⁻²/1×10⁻²)</em>
<em> </em><em>₂=(10dB)㏒₁₀(2.04×10¹⁰)</em>
<em /><em> =(10dB)[㏒₁₀(2.04)+㏒₁₀(10¹⁰)]=10dB[0.32+10]=103dB=100dB</em>
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