Given acceleration a = 5-3t, and its velocity is 7 at time t = 2, the value of s2 - s1 = 7
<h3>How to solve for the value of s2 - s1</h3>
We have
= ![\frac{dv}{dt} =v't = 5-3t\\\\\int\limits^a_b {v'(t)} \, dt](https://tex.z-dn.net/?f=%5Cfrac%7Bdv%7D%7Bdt%7D%20%3Dv%27t%20%3D%205-3t%5C%5C%5C%5C%5Cint%5Climits%5Ea_b%20%7Bv%27%28t%29%7D%20%5C%2C%20dt)
![= \int\limits^a_b {(5-3t)} \, dt](https://tex.z-dn.net/?f=%3D%20%5Cint%5Climits%5Ea_b%20%7B%285-3t%29%7D%20%5C%2C%20dt)
![5t - \frac{3t^2}{2} +c](https://tex.z-dn.net/?f=5t%20-%20%5Cfrac%7B3t%5E2%7D%7B2%7D%20%2Bc)
v2 = 5x2 - 3x2 + c
= 10-6+c
= 4+c
![s(t) = \frac{5t^2}{2} -\frac{t^3}{2} +3t + c](https://tex.z-dn.net/?f=s%28t%29%20%3D%20%5Cfrac%7B5t%5E2%7D%7B2%7D%20-%5Cfrac%7Bt%5E3%7D%7B2%7D%20%2B3t%20%2B%20c)
S2 - S1
![=(5*\frac{4}{2} -\frac{8}{2} +3*2*c)-(\frac{5}{2} *1^2-\frac{1^2}{2} +3*1*c)](https://tex.z-dn.net/?f=%3D%285%2A%5Cfrac%7B4%7D%7B2%7D%20-%5Cfrac%7B8%7D%7B2%7D%20%2B3%2A2%2Ac%29-%28%5Cfrac%7B5%7D%7B2%7D%20%2A1%5E2-%5Cfrac%7B1%5E2%7D%7B2%7D%20%2B3%2A1%2Ac%29)
= 6 + 6+c - 2+3+c
12+c-5+c = 0
7 = c
Read more on acceleration here: brainly.com/question/605631
Answer:
<u>No</u>.
Explanation:
They are not all the same. Moreover, using a fluid that is not approved by the vehicle manufacturer will void the transmission warranty.
Answer:
35
Explanation: I really dont even know, I just used up all my tries on it and got it wrong on every other thing i chose. So it's 35 i believe cause its the only answer i didnt choose.
Answer:Counter,
0.799,
1.921
Explanation:
Given data
![T_{h_i}=200^{\circ}C](https://tex.z-dn.net/?f=T_%7Bh_i%7D%3D200%5E%7B%5Ccirc%7DC)
![T_{h_o}=120^{\circ}C](https://tex.z-dn.net/?f=T_%7Bh_o%7D%3D120%5E%7B%5Ccirc%7DC)
![T_{c_i}=100^{\circ}C](https://tex.z-dn.net/?f=T_%7Bc_i%7D%3D100%5E%7B%5Ccirc%7DC)
![T_{c_o}=125^{\circ}C](https://tex.z-dn.net/?f=T_%7Bc_o%7D%3D125%5E%7B%5Ccirc%7DC)
Since outlet temperature of cold liquid is greater than hot fluid outlet temperature therefore it is counter flow heat exchanger
Equating Heat exchange
![m_hc_{ph}\left [ T_{h_i}-T_{h_o}\right ]=m_cc_{pc}\left [ T_{c_o}-T_{c_i}\right ]](https://tex.z-dn.net/?f=m_hc_%7Bph%7D%5Cleft%20%5B%20T_%7Bh_i%7D-T_%7Bh_o%7D%5Cright%20%5D%3Dm_cc_%7Bpc%7D%5Cleft%20%5B%20T_%7Bc_o%7D-T_%7Bc_i%7D%5Cright%20%5D)
=![\frac{125-100}{200-120}=\frac{25}{80}=C\left ( capacity rate ratio\right )](https://tex.z-dn.net/?f=%5Cfrac%7B125-100%7D%7B200-120%7D%3D%5Cfrac%7B25%7D%7B80%7D%3DC%5Cleft%20%28%20capacity%20rate%20ratio%5Cright%20%29)
we can see that heat capacity of hot fluid is minimum
Also from energy balance
![Q=UA\Delta T_m=\left ( mc_p\right )_{h}\left ( T_{h_i}-T_{h_o}\right )](https://tex.z-dn.net/?f=Q%3DUA%5CDelta%20T_m%3D%5Cleft%20%28%20mc_p%5Cright%20%29_%7Bh%7D%5Cleft%20%28%20T_%7Bh_i%7D-T_%7Bh_o%7D%5Cright%20%29)
=![\frac{\left ( T_{h_i}-T_{h_o}\right )}{T_m}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cleft%20%28%20T_%7Bh_i%7D-T_%7Bh_o%7D%5Cright%20%29%7D%7BT_m%7D)
![T_m=\frac{\left ( 200-125\right )-\left ( 120-100\right )}{\ln \frac{75}{20}}](https://tex.z-dn.net/?f=T_m%3D%5Cfrac%7B%5Cleft%20%28%20200-125%5Cright%20%29-%5Cleft%20%28%20120-100%5Cright%20%29%7D%7B%5Cln%20%5Cfrac%7B75%7D%7B20%7D%7D)
![T_m=41.63^{\circ}C](https://tex.z-dn.net/?f=T_m%3D41.63%5E%7B%5Ccirc%7DC)
NTU=1.921
![And\ effectiveness \epsilon =\frac{1-exp\left ( -NTU\left ( 1-c\right )\right )}{1-c\left ( -NTU\left ( 1-c\right )\right )}](https://tex.z-dn.net/?f=And%5C%20effectiveness%20%5Cepsilon%20%3D%5Cfrac%7B1-exp%5Cleft%20%28%20-NTU%5Cleft%20%28%201-c%5Cright%20%29%5Cright%20%29%7D%7B1-c%5Cleft%20%28%20-NTU%5Cleft%20%28%201-c%5Cright%20%29%5Cright%20%29%7D)
![\epsilon =\frac{1-exp\left ( -1.921\left ( 1-0.3125\right )\right )}{1-0.3125exp\left ( -1.921\left ( 1-0.3125\right )\right )}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%5Cfrac%7B1-exp%5Cleft%20%28%20-1.921%5Cleft%20%28%201-0.3125%5Cright%20%29%5Cright%20%29%7D%7B1-0.3125exp%5Cleft%20%28%20-1.921%5Cleft%20%28%201-0.3125%5Cright%20%29%5Cright%20%29%7D)
![\epsilon =\frac{1-exp\left ( -1.32068\right )}{1-0.3125exp\left ( -1.32068\right )}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%5Cfrac%7B1-exp%5Cleft%20%28%20-1.32068%5Cright%20%29%7D%7B1-0.3125exp%5Cleft%20%28%20-1.32068%5Cright%20%29%7D)
![\epsilon =\frac{1-0.2669}{1-0.0834}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%5Cfrac%7B1-0.2669%7D%7B1-0.0834%7D)
![\epsilon =0.799](https://tex.z-dn.net/?f=%5Cepsilon%20%3D0.799)
Answer:
7.615 kW
Explanation:
Solution in pen paper form in the attachment section