Question

Air conditioners sold in the United States are given a seasonal energy-efficiency ratio (SEER) rating that consumers can use to compare different models. A SEER rating is the ratio of heat pumped to energy input, similar to a COP but using English units, so a higher SEER rating means a more efficient model. You can determine the COP of an air conditioner by dividing the SEER rating by 3.4For inside temperature 25?C and outside temperature 34?C when you'd be using air conditioning, estimate the theoretical maximum SEERrating of an air conditioner. (New air conditioners must have a SEER rating that exceeds 13, quite a bit less than the theoretical maximum, but there are practical issues that reduce efficiency.)

Answer 1

Answer:

112.58

Explanation:

The Coefficient of Performance of any system is denoted by COP=Q/W, where Q is the useful heat supplied or removed and W is the work required by the system. According to the first law of thermoddynamics Qh= Qc + W, where Qh is the heat transfered to the hot reservoir and Qc is the heat collected from the cold reservoir. Substituting the values for W and apllying the limitation for maximum theoretical efficiency we end up with the eqution shown below.

The Coefficient of Performance of air conditioner or COP is denoted by

COP(cool) = Tc/(Th- Tc)

where Tc: the lowest temperature

           Th: the highest temperature

converting the values to Kelvin and adding them in the above equation

COP(cool) = (25+273)/((34+273)-(25+273))

                 = 298/(307-298)

                 = 298/9 = 33.11

From the question, it is stated that COP=SEER/3.4

hence, SEER= COP * 3.4

SEER= 33.11 * 3.4 = 112.58