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Yuliya22 [10]
3 years ago
8

if mechanical advantage and velocity ratio of a machine are equal then the simple machine is called what​

Physics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

hbyjhtcgfcyh

Explanation:

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scoundrel [369]

Answer:

If she bends forward

Explanation:

because the equilibrium of gravity will not stay the same causing her to move forward

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3 years ago
A fixed mass of an ideal gas is heated from 50 to 80℃ at a constant pressure of (a) 1 atm and (b) 3 atm. for which case do you t
ohaa [14]
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3 years ago
Examples of how thermal energy transfer by conduction, convection, or radiation.
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3 0
3 years ago
Two forces are acting on a 2.0 kg object that moves with acceleration 6.0 m/s2 in the positive y-direction. If one of the forces
Strike441 [17]

Answer:

12N

Explanation:

We are given that one of the forces are acting only in the horizontal x-direction. As a force must be applied on an object of mass in order to cause acceleration, the 6.0ms^-2 acceleration is due to the non-horizontal force acting on the 2.0kg object.

Using Newton's Second Law of motion; we know that for a constant mass, force is equal to mass times acceleration, F=ma.

Assuming the other force is acting only in the vertical direction (question doesn't specify, thus we are finding the minimum force to cause this acceleration):

F= 2.0kg * 6.0ms^-2

F=12.0 kgms^-2

F=12 N

3 0
3 years ago
An ultrasound unit is being used to measure a patient's heartbeat by combining the emitted 2.0 MHz signal with the sound waves r
alexandr402 [8]
Hi there, 
for this question we have:
Signal 2.0 MHz = Emitted so we can call it f_e
and we need the Reflected = f_{r}
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted). 
we also know: ΔBeat frequency(max) = 560 Hz = f_{b}
so we have: 
f_{e} - f_{r} = f_{b}
so frequency of Reflected is: 
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz = f_{r}
now you know that Lambda = v/f 
so if we find the lambda with our Emitted then we can find v with the Reflected: 
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m 
=> v_{max} = (lambda)(f_{r} 
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s 
so the v_{max} is equal to 1532 m/s :)))
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day

8 0
3 years ago
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