Answer:
6 rad/s
Explanation:
In a spring the angular frequency is calculated as follows:
where 
is the angular frequency, 
is the mass of the object in this case 
, and 
is the constant of the spring.
To calculate the angular frequency, first we need to find the constant which is calculated as follows:
Where 
is the force: 
, and 
is the distance from the equilibrium position: 
.
Thus the spring constant:
And now we do have everything necessary to calculate the angular frequency:
the angular frequency of the oscillation is 6 rad/s
Answer:
Look at the attachment to see the work. It should be attached right below this, but if it's not, please let me know.
Explanation:
(I've never attached anything before so I'd like to know if it worked)
Answer:
Power = 251.9 Watts
Explanation:
Power = Work Done / Time taken
Power = 3441 / 13.66
Power = 251.9 Joule / Second
Power = 251.9 Watts
Answer:B
Explanation:
Given
First motor has three times as much as power as another
Let the power of smaller motor be P
Therefore bigger motor has power 3 P
and we know that energy 
Larger motor 
Smaller motor 
Therefore smaller motor will do same work if it takes three times the time taken by Larger motor
Answer:
The number of turns in the second coil is more than the coil 1.
Explanation:
The magnetic field lines are the imaginary path on which an isolated north pole moves if it is free to do so.
The tangent at any point to the magnetic field line, gives the direction of magnetic field at that point.
More be the crowd ness of magnetic field lines more is the strength of magnetic field.
Here the crowd ness of magnetic field lines is more in figure 2 , so the magnetic filed in figure 2 is more than 1. It shows that the number of turns in the second coil is more than the 1 and also the current in the coil 2 is more than 1 .
