The earths gravitational pull keeps the moon orbiting around and from straying away from it and into the vast expanses of outer space.
Ok first of all we have to convert in km/hr=Speed
So 30min are 0.5hours
Then we use S= distance/time = 5km/0.5 hrs = 10km/hr —> Jill speed
Then S= d/t = 10km/0.5hrs = 20km/hr —> Scott speed
So Scott rode faster
It seems that you have missed the necessary options for us to answer this question, so I had to look for it. Anyway, here is the answer. You can apply the idea that <span>momentum is constant to solve a problem when the system is not isolated but the time interval when the external forces are exerted is very small. Hope this helps.</span>
I: x = 1/2at²
II: v = at
I+II: x = 1/2a(v²/a²) = 1/2 v²/a
a = 1/2 v²/x
v = 30
x = 49
