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4vir4ik [10]
3 years ago
6

In the morning, John drove to his mother's house in the village at an average speed of 60 kilometers per hour. When he was going

back to town in the evening, he drove more cautiously and his speed was lower. If John went the same distance in the evening as in the morning, what was John's average speed for the entire trip?
Physics
1 answer:
Nuetrik [128]3 years ago
8 0

Answer:

<u>\frac{v2+v1}{2}, where v2= velocity at the end and v1= velocity in the beggining</u>

Explanation:

<u>Asuming that v=K, where k= velocity lower than 60[km/h] we can make an equation for a average speed to entire trip as follows:</u>

<u>The equation of average is: \frac{v2+v1}{2}, where v2= velocity at the end and v1= velocity in the beggining. Where v1=60 [km/h] becouse is the average velocity of half trip, and v2=k.</u>

<u>That means that jhon´s average speed decreses</u>

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A car speeds up from rest to +16 m/ s in 4s. calculate the acceleration
Pani-rosa [81]

The magnitude of acceleration is (change in speed) / (time for the change).

Change in speed = (speed at the end) - (speed at the beginning) =

                                   (16 m/s)  -  (0)  =  16 m/s .

Time for the change  =  4 s .

Magnitude of acceleration = (16 m/s) / (4 s) = 4 m/s per sec = 4 m/s² .


6 0
3 years ago
Read 2 more answers
Andy pushes a box to the right with 5 N of force. Kristen pushes the box to the left with 3 N of force. What will be the resulti
REY [17]
The forces are applied in opposite direction.
So the net force will be the difference of both forces.
net force =5-3=2N

This force will be in direction of 5N(bigger force) means in direction which Andy is pushing.
6 0
2 years ago
A man pulls on his dog's leash to keep him from running after a bicycle. Which term best describes this example?
otez555 [7]
We know the answer doesn't have to do with force because we have not identified a positive or negative axis. 

Depending on what the system we are evaluating is, the sign of the work can change.

If work is done on the system, it is negative, but if work is done by the system, it is positive. 

If the system we are evaluating is the leash, the work is being done by the leash, and therefore, the work is positive.

If the system we are evaluating is the dog, the work is being done on the dog, and therefore, the work is negative.


8 0
2 years ago
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If a 5000-kg is moving at a speed of 43 m/s, what is its momentum?
Eduardwww [97]

Answer:

215000kgm/s

Explanation:

Given parameters:

Mass of the moving body  = 5000kg

Velocity  = 43m/s

Unknown:

Momentum  = ?

Solution:

The momentum of a body is the amount of motion a body possess.

 It is mathematically expressed as:

  Momentum  = mass x velocity

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  Momentum  = 5000 x 43  = 215000kgm/s

4 0
2 years ago
A 1600kg cannon fires a 5kg cannonball horizontally. The exit velocity of the cannonball is 80m/s and the barrel length is 2m. W
evablogger [386]

Answer:

 a = 1600 m / s²

Explanation:

For this exercise we use the kinematics relations,

         v² = v₀² + 2 a x

where v₀ is the initial velocity of the bullet, which as part of rest is zero, for the distance (x) we can assume that the gases accelerate along the entire trajectory of the cannon x = 2m

         a = \frac{v^2}{2x}

let's calculate

         a = \frac{80^2}{2 \ 2}

         a = 1600 m / s²

7 0
3 years ago
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