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rosijanka [135]
3 years ago
13

An object is moving at 10 m/s slows to 6 m/s in 4 seconds. What is its average acceleration?? Help pls!!

Physics
1 answer:
Ivahew [28]3 years ago
6 0
You need to find the acceleration . a=v-vo/t
a=6-10/4
a=-4/4
a=-1m/s/s or -1m/s^2
You’re welcome :)
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Vapor pressure is directly related to the temperature of the liquid. user: in an open system, the vapor pressure is equal to the outside air pressure.

Explanation;

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Answer:

After 15 seconds, the green car will catch up with the blue car

Explanation:

Let the time for the green car to catch up with the blue car be T

When the green car catches up to the blue car, the distances covered by each car after time T will be equal. Also, their velocities at that instant will be equal

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S = 0.5 × 0.2 × T² = 0.1 T²

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Where v = 0.2T, t = T - 7.5 (since the blue car started 7.5 seconds earlier)

S = 0.2T (T - 7.5)

S = 0.2 T² - 1.5T

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0.2T² - 1.5T = 0.1T²

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T(0.1T - 1.5) = 0

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1 year ago
Two solid marbles A and B with a mass of 3.00 kg and 6.50 kg respectively have an elastic collision in one dimension. Before col
Akimi4 [234]

Answer:

va = 4.79 m/s

vb = 1.29 m/s

Explanation:

Momentum is conserved:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

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22.75 = 3v₁ + 6.5v₂

For an elastic collision, kinetic energy is conserved.

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m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²

(3.00) (0)² + (6.50) (3.50)² = (3.00) v₁² + (6.50) v₂²

79.625 = 3v₁² + 6.5v₂²

Two equations, two variables.  Solve with substitution:

22.75 = 3v₁ + 6.5v₂

22.75 − 3v₁ = 6.5v₂

v₂ = (22.75 − 3v₁) / 6.5

79.625 = 3v₁² + 6.5v₂²

79.625 = 3v₁² + 6.5 ((22.75 − 3v₁) / 6.5)²

79.625 = 3v₁² + (22.75 − 3v₁)² / 6.5

517.5625 = 19.5v₁² + (22.75 − 3v₁)²

517.5625 = 19.5v₁² + 517.5625 − 136.5v₁ + 9v₁²

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0 = v₁ (28.5v₁ − 136.5)

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Solving for v₂:

v₂ = (22.75 − 3v₁) / 6.5

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