Answer:
The answer to your question is:
Explanation:
Data
moles H=?
moles of N = 0.0969
moles of NH₃=?
                             N₂ (g)  + 3 H₂ (g)  ⇒   2NH₃ (g)
Process
1.- Set a rule of three to calculate the moles of hydrogen
                          1 mol of nitrogen  -------------   3 moles of hydrogen
                          0.0969 moles of N ----------     x
                          x = (0.0969 x 3) / 1
                          x = 0.2907 moles of hydrogen          
2.- Set a rule of three to calculate the moles of ammonia
                         1 mol of nitrogen --------------  2 moles of ammonia
                         0.0969 mol of N --------------   x
                         x = (0.0969 x 2) / 1
                         x = 0.1938 moles of ammonia                 
 
        
             
        
        
        
Explanation:
1) Initial mass of the Cesium-137= = 180 mg
= 180 mg
Mass of Cesium after time t = N
Formula used :
 
Half life of the cesium-137 = ![t_{1/2}=30 years[p/tex]where,
[tex]N_o](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D30%20years%5Bp%2Ftex%5D%3C%2Fp%3E%3Cp%3Ewhere%2C%0A%3C%2Fp%3E%3Cp%3E%5Btex%5DN_o) = initial mass of isotope
 = initial mass of isotope
N = mass of the parent isotope left after the time, (t)
 = half life of the isotope
 = half life of the isotope
 = rate constant
 = rate constant

Now put all the given values in this formula, we get
 
 Mass that remains after t years.

Therefore, the parent isotope remain after one half life will be, 100 grams.
2)
t = 70 years


 
N = 35.73 mg
35.73 mg of cesium-137 will remain after 70 years.
3) 


N = 1 mg
t = ?
 

t = 224.80 years ≈ 225 years
After 225 years only 1 mg of cesium-137 will remain.
 
        
             
        
        
        
1s2,2s2.2p6,3s2,3p6,3d4,4s2
        
                    
             
        
        
        
Answer : The equilibrium constant for this reaction is, 
Explanation :
The given main chemical reaction is:
 ;
;  
The intermediate reactions are:
(1)  ;
;  
(2)  ;
;  
We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:
(1)  ;
;  
(2)  ;
;  
Thus, the equilibrium constant for this reaction will be:


Thus, the equilibrium constant for this reaction is, 
 
        
             
        
        
        
Answer:
Temp decreased
Explanation:
If the container is sealed and the pressure DEcreases, then the temperature DEcreased 
PV = n RT     n  R   V   are constant   if  P goes down then so does T