Answer:
117.6 m/s downward
Explanation:
The penny is moving with uniform accelerated motion (free fall motion), so we can find its vertical velocity at time t with the following suvat equation:
v = u + at
where
v is the velocity at time t
u is the initial velocity
a is the acceleration
The penny starts at rest, so
u = 0
Also, the acceleration is the acceleration of gravity,
where we have chosen upward as positive direction, so the acceleration is negative, since it is downward.
Substituting t = 12 s, we find the velocity of the penny when it hits the ground:
downward, since the sign is negative.
Answer:
B. When the ball is released, the thrower's arm transfers its energy to the ball.
Answer:
a) 24.692 m/s
b) 19.4 m
Explanation:
To calculate the velocity at the nozzle outflow (V2) we use the Bernoulli equation:
We know that the velocity above the oil surface (V1) and the pressure at the nozzle outflow (P2) are negligible, the height in the exit is zero (Z2) then:
a) The velocity (V2) is:
Substituting the known values we can get the velocity at the out:
Atmospheric pressure= 101000 Pa
Oil density= 0.88x(Water density)=0.88(1000kg/m3)=880kg/m3
b) To calculate the height we have to apply the Bernoulli equation between the outflow and the maximum height (Z3), so:
We know that the velocity above the stream (V3) and the pressure at the nozzle outflow (P2) are negligible, the pressure at the top of the stream (P3) is the atmospheric pressure, then:
Substituting the known values, the height (Z3) is:
Z3=Maximum Height=19.376=19.4 m
<span>A star has a mass that is 1/5 that of earths sun. What will happen to the star as it ages?
It will become a Neutron star.</span>
Elements are made up of the same type of atom and are classified by the number of protons they contain.