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3 years ago

When an element undergoes nuclear transmutation, the result is a completely different

Physics

2 answers:

wolverine [178]3 years ago

3 0

Answer: Element or Isotope

Explanation:

Transmutation of elements is the change that occurs when one chemical element is transformed to another, this happens during nuclear reaction or during radioactive decay.

When this happens, a different element or isotope is formed because there is a change in the proton or neutron within the nucleus of such element.

77julia77 [94]3 years ago

3 0

Answer:

yes, the resulting element will be completely different

Explanation:

nuclear transmutation is the conversion of one chemical element into another chemical element.

through isotope, the new element will be completely different

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At high speeds, a particular automobile is capable of an acceleration of about 0.540 m/s^2. At this rate, how long (in seconds)

Mama L [17]

Answer:

t = 6.68 seconds

Explanation:

The acceleration of the automobile, $a=0.54\ m/s^2$

Initial speed of the automobile, u = 91 km/hr = 25.27 m/s

Final speed of the automobile, v = 104 km/hr = 28.88 m/s

Let t is the time taken to accelerate from u to v. It can be calculated as the following formula as :

$t=\dfrac{v-u}{a}$

$t=\dfrac{28.88-25.27}{0.54}$

t = 6.68 seconds

So, the time taken by the automobile to accelerate from u to v is 6.68 seconds. Hence, this is the required solution.

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Klio2033 [76]

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3 years ago

True or False: The more mass an object has, the faster it will fall.

Elza [17]

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A skier leaves the horizontal end of a ramp with a velocity of 31.0 m/s and lands 156.3 m from the base of a ramp how high is th

BartSMP [9]

<u>Answer:</u>

The height of ramp = 124.694 m

<u>Explanation:</u>

Using second equation of motion,

$s = ut + \frac{1}{2}at^2$

From the question,

u = 31 m/s; s = 156.3 m, a=0

substituting values

$156.3 = 31\times t + 0$

t = $\frac{156.3}{31 }$

= 5.042 s

Similary, for the case of landing

t = 5.042 s; initial velocity, u =0

acceleration = acceleration due to gravity, g = 9.81 $m/s^2$

Substituting in $h = ut + \frac{1}{2}gt^2$

$h = 0 + \frac{1}{2} \times 9.81 \times (5.042)^2$

h = 124.694 m

So height of ramp = 124.694 m

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3 years ago