<span>GPE= mgh = 0.1 kg * 9.8 m/s^2 * 12.5m = 12.25 J</span>
Answer:
Explanation:
Given that,
Initial speed, u = 5.1 m/s
Final speed, v = 6.2 m/s
Time, t = 25 s
We need to find acceleration. We know that,
acceleration = rate of change of velocity
So, her acceleration is .
Answer:
Explanation:
angular momentum of the putty about the point of rotation
= mvR where m is mass , v is velocity of the putty and R is perpendicular distance between line of velocity and point of rotation .
= .045 x 4.23 x 2/3 x .95 cos46
= .0837 units
moment of inertia of rod = ml² / 3 , m is mass of rod and l is length
= 2.95 x .95² / 3
I₁ = .8874 units
moment of inertia of rod + putty
I₁ + mr²
m is mass of putty and r is distance where it sticks
I₂ = .8874 + .045 x (2 x .95 / 3)²
I₂ = .905
Applying conservation of angular momentum
angular momentum of putty = final angular momentum of rod+ putty
.0837 = .905 ω
ω is final angular velocity of rod + putty
ω = .092 rad /s .
Answer:
Question
Explanation:
The independent variable in Part I, the one that is intentionally manipulated, is the
.
The independent variable in Part II, the one that is intentionally manipulated, is the
.
The independent variable in Part III, the one that is intentionally manipulated, is the
.
The independent variable in Part IV, the one that is intentionally manipulated, is the
.
Answer:
1.73 m/s²
Explanation:
Given:
Δx = 250 m
v₀ = 0 m/s
t = 17 s
Find: a
Δx = v₀ t + ½ at²
250 m = (0 m/s) (17 s) + ½ a (17 s)²
a = 1.73 m/s²