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2 years ago

Stop to Think 7.1 Which one is greater- the attraction of the Earth on 1 kg lead or the attraction of 1 kg of led

Physics

1 answer:

Daniel [21]2 years ago

7 0

Answer:

1 kg lead to earth is greater attraction as mass of earth is much more than 1kg lead.

Explanation:

Objects with more mass have more gravity. Gravity also gets weaker with distance. So, the closer objects are to each other, the stronger their gravitational pull is. Earth's gravity comes from all its mass

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raising the temperature of a gas will increase its pressure If which of the following happens the volume is increased but the nu

Nadusha1986 [10]

D, as the others will result in the likelihood of the particles colliding decreasing

Hope it helps))

3 0

2 years ago

What is Acceleration?

earnstyle [38]

Acceleration is the rate of change of velocity

To define acceleration, We need to know more about motion.

Motion: This can be defined as the change in position of a body from one point to another. When an object accelerates, it undergoes motion.

<u>Definition</u>

Acceleration can be defined as the rate of change of velocity. The S.I unit of acceleration is meter-per-squared seconds. (m/s²)

The formula of acceleration is

a = (v-u)/t................. Equation 1

⇒ Where:

a = acceleration
u = initial velocity
v = final velocity
t = time

Hence, Acceleration is the rate of change of velocity

Learn more about acceleration here: brainly.com/question/605631

5 0

1 year ago

Read 2 more answers

Why are light-years more convenient than miles, kilometers, or astronomical units (au) for measuring the distances to stars and

Tomtit [17]

Answer:

sEE BELOW

Explanation:

Well.....because the numbers are 'astronomical'....meaning VERY, VERY , VERY LARGE

5 0

1 year ago

The uniform 100-kg I-beam is supported initially by its end rollers on the horizontal surface at A and B. by means of the cable

Ann [662]

I attached a free body diagram for a better understanding of this problem.

We start making summation of Moments in A,

$\sum M_A = 0$

$P(6cos\theta)-981(4cos\theta)=0$

$P=654N$

Then we make a summation of Forces in Y,

$\sum F_y = 0$

$654+R-981 = 0$

$R=327N$

At the end we calculate the angle with the sin.

$sin\theta = \frac{3m}{4m+2m+2m} = \frac{3m}{8m}$

$\theta = 22.02\°$

8 0

2 years ago

1) A force of 157 N is applied to a box 25o above the horizontal. If it is applied over a distance of 14.5 m how much work is do

vfiekz [6]

Work done is given by

$W = F.d cos\theta$

here we know that

F = 157 N

d = 14.5

$\theta = 25^0$

now from the above formula

$W = (157)(14.5)cos25 = 2063.2 J$

By energy conservation

Initial total potential energy of egg = final total kinetic energy of egg

$mgh = \frac{1}{2}mv^2$

$v = \sqrt{2gh}$

$v = \sqrt{2(9.8)(8.2)}$

$v = 12.7 m/s$

By momentum conservation we know that

$m_1v_1 = (m_1 + m_2)v$

$215(9.5) = (215 + 19.7) v$

$v = \frac{215 (9.5)}{215 + 19.7}$

$v = 8.7 m/s$

by momentum conservation we know that

$m_1v_1 + m_2v_2 = (m_1 + m_2) v$

let direction of velocity of Jay Z car motion is positive direction

now we will say

$1100(-20) + 1475v = (1100 + 1475)(7)$

$1475 v = 2575(7) + 1100(20)$

$v = 27.14 m/s$

Yes Jay Z is overspeeding as his speed is more than speed limit

Tension force in the string will be centripetal force

so here we can say

$T = \frac{mv^2}{R}$

here we know that

m = 0.63 kg

v = 7.8 m/s

R = 0.23 m

$T = \frac{0.63 (7.8)^2}{0.23}$

$T = 166.6 N$

6 0

2 years ago