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3 years ago

Stop to Think 7.1 Which one is greater- the attraction of the Earth on 1 kg lead or the attraction of 1 kg of led

Physics

1 answer:

Daniel [21]3 years ago

7 0

Answer:

1 kg lead to earth is greater attraction as mass of earth is much more than 1kg lead.

Explanation:

Objects with more mass have more gravity. Gravity also gets weaker with distance. So, the closer objects are to each other, the stronger their gravitational pull is. Earth's gravity comes from all its mass

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A biker going around a circular track at constant speed is accelerating. Why?

avanturin [10]

For acceleration, there needs to be three factors that come into play. Either the change in velocity is increasing, decreasing, or it is changing direction. On a circular track, the direction is always changing. Which fits one of the three factors. So your answer would be A.

3 0

4 years ago

A spring is compressed so that it has 7.2 J of elastic potential energy. A 0.3 kg ball is placed on top of the spring. When the

VLD [36.1K]

The height of the ball is 2.45 m.

To calculate the height of the ball, we use the formula below.

<h3>Formula</h3>

E = mgh................ Equation 1

Where:

E = Elastic energy of the spring
m = mass of the ball
h = height of the ball
g = acceleration due to gravity.

make h the subject of the equation

h = E/mg...............Equation 2

From the question,

Given:

E = 7.2 J
m = 0.3 kg
g = 9.8 m/s²

Substitute these values into equation 2

h = 7.2/(0.3×9.8)
h = 7.2/2.94
h = 2.45 m

Hence, The height of the ball is 2.45 m.

Learn more about height here: brainly.com/question/1739912

5 0

3 years ago

Steam at 0.6 mpa, 200 oc, enters an insulated nozzle with a velocity of 50 m/s. It leaves at a pressure of 0.15 mpa and a veloci

vladimir1956 [14]

Answer:

x2 = 0.99

Explanation:

from superheated water table

at pressure p1 = 0.6MPa and

temperature 200 degree celcius

h1 = 2850.6 kJ/kg

From energy equation we have following relation

$\dot m(h1 + \frac{v1^2}{2} +gz1) + Q = \dot m(h2 + \frac{v2^2}{2} +gz1) + W$

$\dot m(h1 + \frac{v1^2}{2} = \dot m(h2 + \frac{v2^2}{2}$

$(h1 + \frac{v1^2}{2} = (h2 + \frac{v2^2}{2}[tex]2850.6 + \frac{50^2}{2} *\frac{1 kJ/kg}{1000 m^2/s^2} = h2 + \frac{600^2}{2} *\frac{1 kJ/kg}{1000 m^2/s^2}$

h2 = 2671.85 kJ/kg

from superheated water table

at pressure p2 = 0.15MPa

specific enthalpy of fluid hf = 467.13 kJ/kg

enthalpy change hfg = 2226.0 kJ/kg

specific enthalpy of the saturated gas hg = 2693.1 kJ/kg

as it can be seen from above value hf>h2>hg, so phase 2 is two phase region. so we have

quality of steam x2

h2 = hf + x2(hfg)

2671.85 = 467.13 +x2*2226.0

x2 = 0.99

5 0

3 years ago

98 points!!!! I will make you brainliest!!! please hurry!!! ASAP!

jeka94

Answer:

-clouds

-precipitation

-RUNOFF

-evaporation

-condensation

-ocean

-RIVERS, STREAMS, AND LAKES

-fresh water

-salt water

-collection area

Hope this helped!

5 0

4 years ago

A 2.50-g bullet, traveling at a speed of 425 m/s, strikes the wooden block of a ballistic pendulum, such as that in the picture.

Gala2k [10]

Answer:

4.88505 m/s

1.21629 m

Explanation:

$m_1$ = Mass of bullet = 2.5 g

$m_2$ = Mass of block = 215 g

$v_1$ = Velocity of bullet = 425 m/s

$v_2$ = Velocity of block

Here, the linear momentum is conserved

$m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}\\\Rightarrow v=\dfrac{2.5\times 10^{-3}\times 425+0.215\times 0}{2.5\times 10^{-3}+0.215}\\\Rightarrow v=4.88505\ m/s$

The speed of the combination of mass is 4.88505 m/s

The energy in the system is conserved

$\dfrac{1}{2}(m_1+m_2)v^2=(m_1+m_2)gh\\\Rightarrow h=\dfrac{v^2}{2g}\\\Rightarrow h=\dfrac{4.88505^2}{2\times 9.81}\\\Rightarrow h=1.21629\ m$

The maximum height the combined mass will reach is 1.21629 m

5 0

3 years ago

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