Answer:
The answer is c
Explanation:
Because all of the Other ones did not make sense
Answer:
10.32 moles of ammonia NH₃
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 6.21×10²⁴ molecules
Number of mole of NH₃ =?
The number of mole of NH₃ can be obtained as follow:
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole
Therefore,
6.21×10²⁴ molecules = 6.21×10²⁴ / 6.02×10²³
6.21×10²⁴ molecules = 10.32 moles
Thus, 6.21×10²⁴ molecules contains 10.32 moles of ammonia NH₃
Answer:
This question lacks options; the options are:
A) They moved more freely
B) They moved closer together.
C) The average speed increased.
D) The average kinetic energy increased
The answer is B
Explanation:
The water in the beaker is described to be in a liquid state of matter. Its temperature decreases from 50°C to 10°C when placed in a freezer by Kiley. This means that heat is gradually being lost as the liquid water undergoes freezing into a solid state.
When water in a liquid state is freezed, it's molecules, which were moving more freely begin to move closer together because the speed at which the particles in the liquid state moved has been reduced.
Answer:
666,480 Joules or 669.48 kJ
Explanation:
We are given;
- Volume of water as 2.0L or 2000 ml
but, density of water is 1 g/ml
- Therefore, mass of water is 2000 g
- Initial temperature as 20 °C
- Final temperature as 99.7° C
Required to determine the heat change
We know that ;
Heat change = Mass × Temperature change × specific heat
In this case;
Specific heat of water is 4.2 J/g°C
Temperature change is 79.7 °C
Therefore;
Heat change = 2000 g × 79.7 °C × 4.2 J/g°C
= 669,480 Joules 0r 669.48 kJ
Thus, the heat change involved is 666,480 Joules or 669.48 kJ
Answer: The final temperature of the system will be 
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of steam = 25 g
= mass of water = 0.2384 kg = 238.4 g (1kg=1000g)
= final temperature = ?
= temperature of steam = 
= temperature of water = 
= specific heat of steam = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![25g\times 1.996J/g^0C\times (T_{final}-116)=-[238.4g\times 4.184J/g^0C\times (T_{final}-8)]](https://tex.z-dn.net/?f=25g%5Ctimes%201.996J%2Fg%5E0C%5Ctimes%20%28T_%7Bfinal%7D-116%29%3D-%5B238.4g%5Ctimes%204.184J%2Fg%5E0C%5Ctimes%20%28T_%7Bfinal%7D-8%29%5D)
Therefore, the final temperature of the system will be
