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diamong [38]
3 years ago
8

Consider the following hypothetical molecular collisions and predict which of the following will form potential products, given

the values for the energy of activation, Ea, and enthalpy of the reaction, ΔH, in combination with the molecular orientation.
Chemistry
1 answer:
Annette [7]3 years ago
7 0

Answer:

The collision theory is defined as the rate of a reaction is proportional to the rate of reactant collisions.

Explanation:

The reacting species should collide with orientation that allows contract between the atoms that will become bonds together in the product.

The collision occurs with adequate energy  to permit mutual penetration of the reacting species. The two physical factors based on the orientation and energy of collision, the following reaction with carbon monoxide with oxygen is considered.

 2CO(g) + O2(g) → 2CO2 (g)

After collision between the carbon monoxide and oxygen the reaction is

 CO(g) + O2(g) → CO2 (g) + O(g)

Based on the theories of chemical reaction the molecules collide with sufficient amount of energy an activated complex is formed.

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16 grams of propane, C 3 H 8 and 20 grams of oxygen, O 2 are reacted to produce carbon dioxide and water. Calculate the volume o
Veseljchak [2.6K]

Answer:

The volume of CO₂ produced is 8.4 L

Explanation:

The mass of propane in the reaction C₃H₈ = 20 grams

The mass of, oxygen, O₂ in the reaction = 20 grams

The produce of the reaction are carbon dioxide, CO₂ and water, H₂O

The balanced equation of the (combustion) reaction can be presented as follows;

C₃H₈ (g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)

Therefore, one mole of propane, C₃H₈, reacts with five moles of oxygen, O₂, to produce three moles of carbon dioxide, CO₂, and four moles of water molecules, H₂O, as steam

The number of moles = Mass/(Molar mass)

The molar mass of propane, C₃H₈ = 44.1 g/mol

The number of moles of propane in 16 grams of propane = 16/44.1 ≈ 0.3628 moles

The molar mass of oxygen, O₂ = 32.0 g/mol

The number of moles of oxygen in 20 grams of propane = 20/32 ≈ 0.625 moles

Therefore;

Given that 1 mole of C₃H₈ reacts with 5 moles of O₂

1 mole of O₂ will react with 1/5 moles of C₃H₈

0.625 moles of O₂ will react with 0.625/5 = 0.125 moles of C₃H₈ to produce 3 × 0.125 = 0.375 moles of CO₂

1 mole of an ideal gas occupies 22.4 L at standard temperature and pressure

Taking CO₂ as an ideal gas, we have;

0.375 mole of CO₂ will occupy 0.375 × 22.4 L = 8.4 L

Therefore, the volume of CO₂ produced = The volume occupied by the 0.375 moles of CO₂ = 8.4 L.

5 0
3 years ago
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