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diamong [38]
3 years ago
8

Consider the following hypothetical molecular collisions and predict which of the following will form potential products, given

the values for the energy of activation, Ea, and enthalpy of the reaction, ΔH, in combination with the molecular orientation.
Chemistry
1 answer:
Annette [7]3 years ago
7 0

Answer:

The collision theory is defined as the rate of a reaction is proportional to the rate of reactant collisions.

Explanation:

The reacting species should collide with orientation that allows contract between the atoms that will become bonds together in the product.

The collision occurs with adequate energy  to permit mutual penetration of the reacting species. The two physical factors based on the orientation and energy of collision, the following reaction with carbon monoxide with oxygen is considered.

 2CO(g) + O2(g) → 2CO2 (g)

After collision between the carbon monoxide and oxygen the reaction is

 CO(g) + O2(g) → CO2 (g) + O(g)

Based on the theories of chemical reaction the molecules collide with sufficient amount of energy an activated complex is formed.

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Industrial production of nitric acid, which is used in many products including fertilizers and explosives, approaches 10 billion
mylen [45]

Answer: 9.361\times 10^{4} kJ

Explanation:

The balanced chemical equation :

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)  \Delta H^0_{rxn}=-902.0kJ

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{7.056\times 10^3g}{17g/mol}=415.1moles

According to stoichiometry:

4 moles of NH_3 produces = 902.0 kJ of energy

415.1 moles of NH_3 produces =\frac{902.0}{4}\times 415.1=9.361\times 10^{4} kJ of energy

Thus the change in enthalpy is 9.361\times 10^{4} kJ

5 0
4 years ago
In 3–5 sentences, explain how meteorologists use weather data to predict the probability of a catastrophic wildfire.
allsm [11]

Answer and Explanation:

Meteorologists use meteorological data to assess current temperature and precipitation rates and even make projections of these rates in future times. If high temperature rates combined with low rainfall can cause catastrophic fires to occur, then analyzing data on these factors and making projections on them is essential to prepare for those fires.

5 0
3 years ago
What is the maximum magnification of a compound light microscope?
igor_vitrenko [27]

Answer: 100x

Explanation:

The actual power or magnification of a compound optical microscope is the product of the powers of the ocular (eyepiece) and the objective lens. The maximum normal magnifications of the ocular and objective are 10× and 100× respectively, giving a final magnification of 1,000×.

8 0
3 years ago
Read 2 more answers
How many grams of Br are in 345g of CaBr2?
nadya68 [22]

Answer:

276g of Br are present

Explanation:

To solve this question we need to find the moles of CaBr2 using its molar mass -CaBr2: 199.89g/mol-. As 1 mole of CaBr2 contains 2 moles of Br we can find the moles of Br and its mass:

<em>Moles CaBr2:</em>

345g * (1mol/199.89g) = 1.7259 moles CaBr2

<em>Moles Br:</em>

1.7259 moles CaBr2 * (2mol Br / 1mol CaBr2) = 3.4519 moles Br

<em>Mass Br -Molar mass: 79.904g/mol-</em>

3.4519 moles Br * (79.904g/mol) = 276g of Br are present

4 0
3 years ago
ZILLDIFFEQMODAP11 3.1.021. My Notes Ask Your Teacher A tank contains 150 liters of fluid in which 10 grams of salt is dissolved.
SSSSS [86.1K]

Answer:

Therefore, the number of grams of salt in the tank at time t is A(t) = 150-140 e^{-\frac{t}{30} }

Explanation:

Given:

Tank A contain V_{1} = 150 lit

Rate \alpha = 5 \frac{L}{min}

Dissolved salt A = 10 gm

Salt pumped in one minute is 4 \frac{L}{min}

Salt pumped out is \frac{5L}{150L} = \frac{1}{30} of initial amount added salt.

To find A(t)

  \frac{dA}{dt}  = Rate _{in} - Rate _{out}

  A' = 5 - \frac{A}{30}

  A' + \frac{A}{30} = 5

Solving above equation,

  I .F   = e^{\int\limits {p} \, dt }

   y = e^{\int\limits {\frac{1}{30} } \, dt }

   y = e^{\frac{t}{30} }

(Ae^{\frac{t}{30} }  )' = 5 e^{\frac{t}{30} } + c

Integrating on both side,

Ae^{\frac{t}{30} } =  5 \times 30 e^{\frac{t}{30} } +c

Add e^{-\frac{t}{30} } on above equation,

 A = 150 + ce^{-\frac{t}{30} }

Here given in question,A(t=0) = 10

 10 =150 +c

   c = -140

Put value of constant in above equation, and find the number of grams of salt in the tank at time t.

 A(t) = 150-140 e^{-\frac{t}{30} }

Therefore, the number of grams of salt in the tank at time t is A(t) = 150-140 e^{-\frac{t}{30} }

7 0
3 years ago
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