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Mila [183]
3 years ago
8

If salt (5.99 × 10–6 mol) is dissolved in 1.50 × 10–2 L of water, which expression can be used to find the molarity of the resul

ting solution?
Chemistry
2 answers:
UkoKoshka [18]3 years ago
5 0
The answer is: 3.99 × 10–4 M
Citrus2011 [14]3 years ago
5 0

Answer:

the answer is c. hope it helps

Explanation:

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Consider the reaction. mc014-1.jpg How many grams of methane should be burned in an excess of oxygen at STP to obtain 5.6 L of c
garri49 [273]
The reaction for the combustion of methane can be expressed as follows.
                           CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
                            moles of CO2 = (5.6 L) / (22.4 L/1 mole)
                             moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
                              moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
                                                    = 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane. 
5 0
3 years ago
Read 2 more answers
Calculate the volume of mercury with a density of 14.6 g/mL and a mass of 1.00 g. Please include a numeric value only with signi
spayn [35]
The volume is 0.06849315

3 0
3 years ago
What is the total pressure in atmosphere (atm) of a gas mixture containing argon gas at 0.28 atm, helium gas at 760 mm Hg, and n
siniylev [52]

Answer:

I dont know, sorry!

4 0
3 years ago
I need help in Chemistry
Komok [63]
What kind of a help you need?
6 0
4 years ago
What is the rate constant for the reaction 2a+b→c? (the initial rate was measured at several different reactant concentrations)
ozzi
To find the rate constant we can write a rate expression for the following reaction:

2A + B → C

A rate expression is written as some rate constant multiplied by the concentrations of the reactants, with each concentration raised to the power of the molar coefficient. [A] has a coefficient of 2, and [B] has a coefficient of 1. Therefore, we get the following rate expression:

rate = k[A]²[B]

We are given a table of values and we can enter the three variable to solve for k.

k = (rate)/([A]²[B])
k = (0.035)/((0.05)²(0.05))
k = 280

We can confirm if the value for k is correct by using another set of concentrations, along with the rate constant and solve for the rate.

rate = 280 [0.10]²[0.05]
rate = 280 (0.01)(0.05)
rate = 0.14

The value we solved for agrees with the rate provided in the table, therefore we know our value for the rate constant is correct which is k = 280.
6 0
3 years ago
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