All categories

3 years ago

How much ATP is produced from a single glucose molecule in each chemical pathway?

Chemistry

2 answers:

vagabundo [1.1K]3 years ago

6 0

Glycolysis yields 2 ATP molecules, Kreb's cycle yields 2 ATP molecules, ETS yields 34 ATP, molecules

AURORKA [14]3 years ago

3 0

<h2>Answer : 38 ATP molecules</h2><h3>Explanation :</h3>

After each cellular respiration cycle there are ATP molecules obtained after oxidizing each glucose molecule

Out of which 2 ATP molecules are obtained from glycolysis cycle, 2 ATP molecules from the Krebs cycle, and about 34 ATP molecules from the electron transport system.

So, in all 2 + 2 + 34 = 38 ATP molecules.

You might be interested in

calculate the number of coulombs of positive charge in 250cm 3 of (neutral) water. (hint: a hydrogen atom contains one proton; a

Sidana [21]

Number of coulombs of positive charge in 250cm^3 water is 1.3×10^7 C

The volume of 250 cm^3 corresponds to a mass of 250 g since the density of water is 1.0 g/cm^3

This mass corresponds to 250/18 = 14 moles since the molar mass of water is 18. There are ten proton (each with charge q = +e) in each molecule of $H_{2}O$ So,

Q = 14NA q =14(6.02×10^23)(10)(1.60×10^−19C) = 1.3×10^7 C.

Mass is the quantity of matter in a physical body. It is also a measure of the body's inertia, the resistance to acceleration when a net force is applied. An object's mass also determines the strength of its gravitational attraction to other bodies.

Learn more about mass here:

brainly.com/question/17067547

#SPJ4

3 0

1 year ago

Which choice gives the correct oxidation numbers for all three elements in rb2so3 in the order that the elements are shown in th

vlabodo [156]

<h3>Answer:</h3>

Rb = + 1

S = + 4

O = - 2

<h3>Explanation:</h3>

Oxidation states of the elements were calculated keeping in mind the basic rules of assigning oxidation states which included assignment of +1 charge to first group elements i.e. Rubidium (Rb) and assignment of -2 charge to Oxygen atom. Then the oxidation state of Sulfur was calculated as follow,

Rb₂ + S + O₃ = 0

Above zero (0) means that the overall molecule is neutral.

Putting values of Rb and O,

(+1)₂ + S + (-2)₃ = 0

(+2) + S + (-6) = 0

+2 + S - 6 = 0

S - 6 = -2

S = -2 + 6

S = + 4

7 0

3 years ago

Assume you mixed 5 µl of your cod fish homogenate with 195 µl working solution. The fluorometer displays a measurement of 12.2 µ

11111nata11111 [884]

Answer:

Hallo

Explanation:

I took that question

3 0

3 years ago

Mixture of 120 grams of KClO3 and 300 grams of water until all of the KClO3 has dissolved. At what temperature does this occur?

lozanna [386]

240°C is required to dissolve 120 grams of KClO₃ in 300 g of water.

Explanation:

As per the solubility curve graph of different salts dissolved in 100 g of water, it can be noted that the KClO₃ gets saturated at 100 °C with the solubility of 59 g in it. But here the water is taken as 300 g and the salt is taken as 120 g. The graph shows the solubility of grams of salt in 100 g of water.

So, then we have to find what is the gram of salt present in 100 g of water for the present sample.

300 g of water contains 120 grams of salt.

Then, 1 g of water will contain $\frac{120}{300}$ g of salt.

Then, 100 g of water will contain $\frac{120}{300}*100$ of salt. This means, 100 g of water will contain 40 g of salt in it.

Then, if we check the graph, the corresponding x-axis point on the curve for the y-axis value of 40 g will give us the temperature required to dissolve the salt in water. So 80°C will be required to dissolve 40 g of salt in 100 g of water.

Then, in order to get the temperature required to dissolve 120 g in 300 g of water, multiply the temperature by 3, which will give the result as 80×3=240 °C.

So, 240°C is required to dissolve 120 grams of KClO₃ in 300 g of water.

8 0

3 years ago

The distance between any two successive places where the shape of the wave repeats itself

Anit [1.1K]

Wave length is the answer.

5 0

3 years ago

Read 2 more answers