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2 years ago

What is the change in electrons for nitrogen in the following reaction?

Chemistry

2 answers:

hammer [34]2 years ago

6 0

Nitrogen loses three electrons. Brainliest would be much appreciated.

galina1969 [7]2 years ago

4 0

Nitrogen lose 3 eletrons
And sulphur gain 2 eletrons.

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An element with the valence electron configuration 4s24p4 would form a monatomic ion with a charge of fill in the blank 5 . In o

nordsb [41]

Answer:

Charge= -2.

Gains two electron into the 4p^4 to become 4p^6.

Explanation:

The element in the periodic table/chart that matches with the valence electron configuration is Selenium with full electron configuration of [Ar] 3d^10 4s^2 4P^4 which is a non-metal that is found in group 4 of the periodic table/chart.

Selenium can receive 2 more electrons on the 4p^4 to give a -2(minus 2) ion that is Se^2-.

Selenium can also loose 2 electron from 4s^2 to give a +2 ion that is Se^2+.

Selenium can also loose 2 electrons from 4s^2 and 2 electrons from 4p^4 to form Se^4+.

Selenium can also loose 2 electrons from 4s^2 and 4 electrons from 4p^4 to form Se^6+.

Thus, in order to form a monatomic ion with a charge(we will be making use of the most stable one). Thus, it will gain two more electron since this is easier to become 4s^2 4p^6.

4 0

2 years ago

Show the equation how many grams of Mg(OH)2 would be produced from 4 mol KOH?

Sindrei [870]

Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂

moles Mg(OH)₂ = 4 x 1 / 2

= 2 moles of   Mg(OH)₂

molar mass Mg(OH)₂ = 58g/mol

mass of   Mg(OH)₂ = n x mm

mass of  Mg(OH)₂ = 58 x 2

= 116 g of <span> Mg(OH)₂</span>

hope this helps!

8 0

2 years ago

Imagine you had HCl with a concentration of exactly 0.10 mol/dm3. If 0.023 dm3 of a sodium hydroxide solution, NaOH (aq), could

polet [3.4K]

Answer:

Explanation:

Step 1: Calculate the amount of sodium hydroxide in moles

Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3

Rearrange:

Concentration in mol/dm3 =

Amount of solutein mol = concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide = 0.100 × 0.0250

= 0.00250 mol

Step 2: Find the amount of hydrochloric acid in moles

The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

So the mole ratio NaOH:HCl is 1:1

Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl

Step 3: Calculate the concentration of hydrochloric acid in mol/dm3

Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3

Concentration in mol/dm3 =

= 0.125 mol/dm3

Step 4: Calculate the concentration of hydrochloric acid in g/dm3

Relative formula mass of HCl = 1 + 35.5 = 36.5

Mass = relative formula mass × amount

Mass of HCl = 36.5 × 0.125

= 4.56 g

So concentration = 4.56 g/dm3

8 0

2 years ago

What is the chemical symbol for gold?

irinina [24]

The chemical symbol for gold is AU

3 0

3 years ago

Read 2 more answers

Which of these is a pure substance

Galina-37 [17]

Both A and B are the answer.

4 0

3 years ago