Question

The decomposition of potassium chlorate into kcl & o2 is used as a source of oxygen in the laboratory. How many moles of potassium chlorate are needed to produce 15 mol of oxygen gas?

Answer 1

Answer:

10moles of kcl

Explanation:

2 K C l O3 →  2 K C l  +  3 O 2

Notice that you have a  2 : 3  mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you'll always produce 2/3 times more moles of the latter.

15 mol of O2 * ((2mol of KCLO3)/(3mol of O2))= 15*2/3=10 Mol