The answer is d. 2 hope this helps
Answer: A) The mass of the cup of frozen water is 12 grams which means the mass did not change
Explanation:
The mass of water did not change, because the amount of matter is the same: by the law of mass conservation you can assure that the mass of water (12 grams) is the same at the begining than the end.
Both in the physical changes (as in the case of the changes in the phases of the matter) and in the chemical changes, the law of conservation of the mass is obeyed. Therefore, assuming that the liquid water did not spill from the sealed container during the night, the mass remained constant (12 grams).
Regarding the fact that Josh noticed the cup had cracked on its sides, you must observe that water is an exception to the common behavior of the matter: most substances shrink when pass from liquid state to solid state due to the fact that the particles (atoms, molecules or ions) lose kinetic energy and they the approach each other occupying less space.
Being the density inversely relatated to the volume (density = mass / volume), this increase on volume means that the substances will increase its density when pass from liquid to solid.
But water is a remarkable exception. Water density reaches its maximum at about 4°C, which means that solid water (0°C) is less dense than liquid water.
Hence, ice (solid water) will ocuppy more space (more volume) than the same amount of liquid water, which is the reason why the liquid water in the plastic cup expanded when it froze, cracking the cup.
The awnser is A :)
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Answer:
1185.0 J.
Explanation:
- The amount of heat needed to accomplish this process can be calculated using the formula:
<em>Q = m.C.ΔT</em>, where,
Q is the amount of heat needed,
m is the mass of the copper <em>(m = 47.35 g)</em>,
C is the specific heat of Cu<em> (C = 0.385 J/g.°C)</em>,
ΔT is the temperature difference (the final temperature - the initial temperature <em>(ΔT = 85.0 - 20.0 = 65.0 °C)</em>.
<em>∴ The amount of heat needed Q = m.C.ΔT </em>= (47.35 g) (0.385 J/g.°C) (65.0 °C) = 1184.933 J ≅ 1185.0 J.
Answer:
759779.6 torr
Explanation:
Initial volume, V₁ = 4001 mL
Final volume, V₂ = 3002 mL
Initial pressure, P₁ = 750.1 atm
We need to find the final pressure at a constant temperature. Let it be P₂. 
We know that,
1 atm = 760 torr
So,
999.71 atm = 759779.6 torr
Hence, there will be 759779.6 torr pressure.
