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Gnoma [55]
3 years ago
13

Smaller mammals use proportionately more energy than larger mammals; that is, it takes more energy per gram to power a mouse tha

n a human. A typical mouse has a mass of 20 g and, at rest, needs to consume 3.0 Cal each day for basic body processes. If a 68 kg human used the same energy per kg of body mass as a mouse, how much energy would be needed each day?
Physics
1 answer:
timama [110]3 years ago
3 0

Answer:

10,200 Cal. per day

Explanation:

The mouse consumes 3.0 Cal each day, and has a mass of 20 grams. We can use this data to obtain a ratio of energy consumption per mass

\frac{3.0 \ Cal}{20 g} = 0.15 \frac{Cal}{g}.

For the human, we need to convert the 68 kilograms to grams. We can do this with a conversion factor. We know that:

1 \ kg = 1000 \ g,

Now, we can divide by 1 kg on each side

\frac{1 \ kg}{1 \ kg} = \frac{1000 \ g}{1 \ kg},

1 = \frac{1000 \ g}{1 \ kg}.

Using this conversion factor, we can obtain the mass of the human in grams, instead of kilograms. First, lets take:

mass_{human} = 68 \ kg

We can multiply this mass for the conversion factor, we are allowed to do this, cause the conversion factor equals 1, and its adimensional

mass_{human} = 68 \ kg * \frac{1000 \ g}{1 \ kg}

mass_{human} = 68,000 g

Now that we know the mass of the human on grams, we can multiply for our ratio of energy consumption

68,000 \ g * 0.15 \frac{Cal}{g} = 10,200 \ Cal

So, we would need 10,200  Cal per day.

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ludmilkaskok [199]

Answer:

k = 0.5 MN/m

Explanation:

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Speed of the rail car, v = 1 m/s

The Kinetic energy(KE) of the railcar is given by the equation:

KE = 0.5 mv²

KE = 0.5 * 5000 * 1²

KE = 2500 J

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The potential energy(PE) stored in the spring is given by the equation:

PE = 0.5kx²

PE = 0.5 * k * 0.1²

PE = 0.005k

According to the principle of energy conservation, Kinetic energy of the railcar equals the potential energy stored in the spring

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4 years ago
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Diameter of the circular tip, d = 1.2 mm = 0.0012 m

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