A 70.0 kg person climbs stairs, gaining 3.90 meters in height. Find the work done (in J) to accomplish this task.
1 answer:
Answer:
Work done, W = 2675.4 J
Given:
mass, m = 70.0 kg
height, H = 3.90 m
Solution:
According to the question, as the person jumps the stairs up, there is an increase in the potential energy of the person which is provided by the work done in climbing the stairs and is given by:
Work done, W = mgH
where
g = acceleration due to gravity =
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Answer:
0.5
Explanation:
Data provided in the question:
The angle between their transmission axes, θ = 60°
Now,
We have the relation,
I₁ = I₀cos²θ
where,
I₁ is the intensity of the transmitted light
I₀ is the intensity of the incident light
on rearranging, we get
=cos²60°
or
=0.5
Answer:
0.48 W
Explanation:
Given that:
the mass of the steel ball = 0.0367 kg
C = 0.270 N
g (acceleration due to gravity) = 9.8
Now;
At Terminal Velocity Weight is balance by drag force
mg =Cv
Making v the subject of the formula:we have:
v = 1.332 m/s
Thus, the Rate at which gravitational energy is converted to thermal energy once the ball reaches terminal velocity is:
P=Fv
P = mgv
P=0.48 W