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xxMikexx [17]
3 years ago
6

Why does pressure change with elevation and depth?

Physics
2 answers:
Minchanka [31]3 years ago
5 0
<span>For any "block" of fluid, the pressure at the bottom times the area must equal the weight plus the pressure at the area times the area, if equilibrium is to be maintained. If not, the "block" of air (some of it at least) will move down or up. Therefore the pressure at the bottom is always higher.

Hope this helps :)
</span>
nasty-shy [4]3 years ago
3 0
<span>the deeper you go the more pressure...that's for depth</span>
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A battery charges a parallel-plate capacitor fully and then is removed. The plates are immediately pulled apart. (With the batte
Assoli18 [71]

Answer:

<em>There will be an increase in potential difference.</em>

Explanation:

As we know that the potential difference depends upon the capacitance.

ΔV = Q/C

When battery is disconnected the charge remains constant on the plates but the capacitance decreases. As the capacitance has an inverse relation with the potential difference, there will be an increase in it.

In addition to that the potential difference can also be defined as the product of field and distance between the plates. As the charge is constant so the field is constant. Upon increasing the separation between the plates the potential difference will also increased.

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3 years ago
Do we include signs if we calculate Electric field strength?
expeople1 [14]
Yes because if not people wouldn't understand how did you calculate electric field strength.
6 0
3 years ago
M (b) Calculate the speed of an electron that is accelerated through the same electric potential difference.
MaRussiya [10]

The speed of a electron that is accelerated from rest through an electric potential difference of 120 V  is 6.49\times10^6m/s

<h3>How to calculate the speed of the electron?</h3>

We know, that the  energy of the system is always conserved.

Using the Law of Conservation of energy,

\triangle K+\triangle U=0

Here, K is the kinetic energy and U is the potential energy.

Now, substituting the formula of U and K, we get:

(\frac{1}{2} mv^2)+(-q\triangle V) =0------(1)

Here,

m is the mass of the electron

v is the speed of the electron

q is the charge on the electron

V is the potential difference

Let v_f and v_i represent the final and initial speed.

Here, v_i =0

Solving for v_f, we get:

v_f=\sqrt{\frac{-2q\triangle V}{m} }

=\sqrt{\frac{2\times1.602\times10^{-19}\times 120}{9.109\times10^{-31}} }

=6.49\times10^6m/s

To learn more about the conservation of energy, refer to:

brainly.com/question/2137260

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4 0
1 year ago
A 53.0 kg sled is sliding on snow with μk=0.110. how much friction force does it feel?
Anon25 [30]

Answer:

57N

Explanation:

F_F = \mu F_N = \mu mg = 0.11 \times 53 kg \times 9,8 \frac{m}{s^{2} }

6 0
2 years ago
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If 100 kg person weighed 400 N on the planet Zorg,
Brut [27]

Answer:

<u>4 m/s²</u>

Explanation:

<u>Formula</u>

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<u>Solving</u> :

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5 0
2 years ago
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