Answer:
a) b) d)
Explanation:
The question is incomplete. The Complete question might be
In an inertial frame of reference, a series of experiments is conducted. In each experiment, two or three forces are applied to an object. The magnitudes of these forces are given. No other forces are acting on the object. In which cases may the object possibly remain at rest? The forces applied are as follows: Check all that apply.
a)2 N; 2 N
b) 200 N; 200 N
c) 200 N; 201 N
d) 2 N; 2 N; 4 N
e) 2 N; 2 N; 2 N
f) 2 N; 2 N; 3 N
g) 2 N; 2 N; 5 N
h ) 200 N; 200 N; 5 N
For th object to remain at rest, sum of all forces must be equal to zero. Use minus sign to show opposing forces
a) 2+(-2)=0 here minus sign is to show the opposing firection of force
b) 200+(-200)=0
c) 200+(-201)
0
d) 2+2+(-4)=0
e) 2+2+(-2)0
f) 2+2+(-3) 0; 2+(-2)+30
g) 2+2+(-5)0; 2+(-2)+50
h)200 + 200 +(-5)0; 200+(-200)+50
Answer:
The oxidation number of a monatomic (composed of one atom) ion is the same as the charge of the ion. For example, the oxidation numbers of K+, Se2−, and Au3+ are +1, -2, and +3, respectively. The oxidation number of oxygen in most compounds is −2.
Explanation:
Answer:
false.
Explanation:
If a object is at rest it does not means that no force is acting on the object.
There can be a scenario that all to forces acting on the object balance each other and the net force required for motion is zero.
So, the given statement is false.
Answer:
The P site
Explanation:
After the formation of peptide linkage, the trna of P site becomes free, more to the E site and then slip away. The A site trna has dipeptide instead of a single aminoacid.
In the prescence of translocase and energy from GTP, the ribosome move in such a way the peptidyl bearing trna of A site come to lie with P sit. This exposes next codon to A site. A new aminoacid trna complex reaches the fresh codon exposed at A site.
Answer:
“A mountain of uranium” is an indefinable amount of uranium. If it means uranium ore as found in nature, then the concentration of uranium is orders of magnitude too low for any type of reaction.
Explanation:
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