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3 years ago

Pls help needs to be done soon thxs

Physics

2 answers:

Pie3 years ago

8 0

Answer:

Valence electrons are the electrons in the outermost shell, or energy level, of an atom.

Example:

Oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell.

const2013 [10]3 years ago

4 0

Is the electrons in the energy shell of an atom

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Please help me someone !

san4es73 [151]

Answer:

The object is moving at constant speed.

Explanation:

The spaces between the dots are equal.

7 0

3 years ago

You are holding one end of an elastic cord that is fastened to a wall 3.0 m away. You begin shaking the end of the cord at 2.3 H

Karo-lina-s [1.5K]

Answer:

Time take to fill the standing wave to the entire length of the string is 1.3 sec.

Explanation:

Given :

The length of the one end $x=$ $3m$ , frequency of the wave $f$ = 2.3 Hz, wavelength of the wave λ = 1 m.

Standing wave is the example of the transverse wave, standing wave doesn't transfer energy in a medium.

We know,

∴ $v = f$ λ

Where $v =$ speed of the standing wave.

also, ∴ $v=\frac{x}{t}$

where $t =$ time take to fill entire length of the string.

Compare above both equation,

⇒ $t =$ $\frac{3}{2.3}$ sec

$t = 1.3sec$

Therefore, the time taken to fill entire length 0f the string is 1.3 sec.

7 0

3 years ago

Which of the following is one of the three main fuels that a star uses for fusion

Colt1911 [192]

Hydrogen, helium, and carbon.

8 0

3 years ago

Read 2 more answers

The slope of a good speed Time indicates ?

11Alexandr11 [23.1K]

The answer would be acceleration.

8 0

3 years ago

Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23

Sloan [31]

Answer:

The ratio is $\frac{T_1}{T_2} = 3.965$

Explanation:

From the question we are told that

The radius of Phobos orbit is R_2 = 9380 km

The radius of Deimos orbit is $R_1 = 23500 \ km$

Generally from Kepler's third law

$T^2 = \frac{ 4 * \pi^2 * R^3}{G * M }$

Here M is the mass of Mars which is constant

G is the gravitational constant

So we see that $\frac{ 4 * \pi^2 }{G * M } = constant$

$T^2 = R^3 * constant$

=> $[\frac{T_1}{T_2} ]^2 = [\frac{R_1}{R_2} ]^3$

Here $T_1$ is the period of Deimos

and $T_1$ is the period of Phobos

$[\frac{T_1}{T_2} ] = [\frac{R_1}{R_2} ]^{\frac{3}{2}}$

=> $\frac{T_1}{T_2} = [\frac{23500 }{9380} ]^{\frac{3}{2}}]$

=> $\frac{T_1}{T_2} = 3.965$

8 0

3 years ago