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Alexxx [7]
3 years ago
13

Pls help needs to be done soon thxs

Physics
2 answers:
Pie3 years ago
8 0

Answer:

Valence electrons are the electrons in the outermost shell, or energy level, of an atom.

Example:

Oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell.

const2013 [10]3 years ago
4 0
Is the electrons in the energy shell of an atom
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If a current is two amps and the resistance is 3 ohms, how much voltage was needed?
Hunter-Best [27]

Answer:

6 V

Explanation:

We can solve the problem by using Ohm's law:

V=RI

where

V is the voltage in the circuit

R is the resistance

I is the current

In this problem, we know the current, I=2 A, and the resistance, R=3 \Omega, therefore we can find the voltage in the circuit:

V=RI=(3 \Omega )(2 A)=6 V

7 0
3 years ago
While brayden is traveling along a straight interstate highway, he notices that the mile marker reads 260. Brayden travels until
Yuki888 [10]

Answer:

<em>displacement = -85 miles</em>

Explanation:

<u>Displacement </u>

It's a magnitude used to measure the linear space between two points. It's computed as the subtraction of the final position minus the initial position which results in a vector. Notice the displacement only depends on the initial and final positions and not on the path the object has traveled.

Brayden starts to measure his position when the mile marker reads 260. Then he travels to the 150-mile marker and goes back to the 175-mile marker, his final position. As mentioned, the displacement only depends on the relative positions, so

displacement = 175 - 260 = -85 miles

5 0
4 years ago
A ski lift has a one-way length of 1 km and a vertical rise of 200 m. The chairs are spaced 20 m apart, and each chair can seat
rusak2 [61]

Power is needed for (1) acceleration and (2) lifting the loaded chairs. These two parts can be calculated separately and then added together.

(1) Power for acceleration:

The final speed of the lift is

V=(10 km/h)(1 h×1000 m60 sec×1 km)=2.887 m/s.

Then the power needed is

Pa=12m(V2−V20)/Δt=12(50×250 kg)(2.778 m/s)2=9.6 kW.

(2) Power for lift

Assume that the acceleration is constant (i.e. power supply is constant), its value will be

a=ΔVΔt=2.778 m/s5 s=0.556 m/s2.

Then the vertical lift during acceleration will be

(12at2)×(2001000)=1.36 m.

Hence, the power needed to increase the potential energy of the lift is

Pg=mgΔhΔt=(50×250 kg) (9.89 m/s2)(1.36 m)/(5 s)=3.41 kW.

Then the total Power required is

Ptotal=Pa+Pg=9.6+34.1=43.7 kW.

Learn more about potential energy at

brainly.com/question/14427111

#SPJ4

4 0
2 years ago
Which sphere does the frog belong to?
LiRa [457]

Answer:

what

Explanation:

3 0
4 years ago
Total energy of an orbiting satellite is negative of its Kinetic or potential energy​
Over [174]
Total energy of an orbiting satellite is negative of Its [Kinetic energy].
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3 years ago
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