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4 years ago

Huryyy

Physics

2 answers:

zmey [24]4 years ago

3 0

The transfer is perpendicular

Surprised
I knew this<span />

erica [24]4 years ago

3 0

Answer:

The transfer of energy is perpendicular to wave motion.

Explanation:

There is two type of waves in which the classification is done by medium motion of particles.

1) Transverse waves : Here the medium molecules will move perpendicular to the wave propagation. So we can say that here energy is transferred perpendicular to the propagation of wave.

2) Longitudinal waves : Here medium molecules will move parallel to the wave propagation. So here we can say that medium molecules will oscillate parallel to the wave propagation.

So here when girl jump on the stretched string then in that case the wave propagated in the string will be transverse wave and hence the correct answer will be

The transfer of energy is perpendicular to wave motion.

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What type of intermolecular force happens with a polar covalent molecule when dipoles are created due to un-equal sharing of ele

Semmy [17]

Answer:

Dipole-dipole interaction force

Explanation:

When one of the constituent atom of the covalent bonding is at least 1.5 times more electronegative than the other atom sharing the electron in the covalent bond then the shared pair of electrons are shifted towards the more electronegative atom developing a partial negative charge on it and similarly develops an equal partial positive charge on the other atom involved in the covalent bond.

This happens in water molecules and the resulting dipole is the cause of hydrogen bonding between two molecules of water. Hydrogen bond also exists in (HF) hydrogen fluoride molecules.

5 0

4 years ago

2) A skier stands at rest and begins to ski downhill with an acceleration of 3.0 m/s² {downhill). What is

Finger [1]

Answer:

337.5m

Explanation:

<u>Kinematics</u>

Under constant acceleration, the kinematic equation holds:

$s=\frac{1}{2}at^2+v_ot+s_o$ , where "s" is the position at time "t", "a" is the constant acceleration, " $v_o$ " is the initial velocity, and $s_o$ is the initial position.

<u>Defining Displacement</u>

Displacement is the difference in positions: $s-s_o$ or $\Delta s$
$s=\frac{1}{2}at^2+v_ot+s_o$

$s-s_o=\frac{1}{2}at^2+v_ot$

$\Delta s=\frac{1}{2}at^2+v_ot$

<u>Using known information</u>

Given that the initial velocity is zero ("skier stands at rest"), and zero times anything is zero, and zero plus anything remains unchanged, the equation simplifies further to the following:

$\Delta s=\frac{1}{2}at^2+v_ot$

$\Delta s=\frac{1}{2}at^2+(0)*t$

$\Delta s=\frac{1}{2}at^2+0$

$\Delta s=\frac{1}{2}at^2$

So, to find the displacement after 15 seconds, with a constant acceleration of 3.0 m/s², substitute the known values, and simplify:

$\Delta s=\frac{1}{2}at^2$

$\Delta s=\frac{1}{2}(3.0[\frac{m}{s^2}])(15.0[s])^2$

$\Delta s=337.5[m]$

5 0

2 years ago

Three identical lights are connected in series to a 12V battery. How does the brightness of each light compare?

kodGreya [7K]

Answer: They are identical brightness

Explanation:

If the lights are assumed to be resistance bulbs

Each light has the same current and will each drop one third of the supply voltage.

8 0

3 years ago

A circular loop of wire lies in the plane of your screen. An increasing magnetic field (produced by another source) points out o

Rashid [163]

Answer:

clockwise direction

Explanation:

Direction of induced current is found with the help of Lenz's law . According to this law , the direction of induced current is such that it tries to neutralize or oppose the reason which creates this current .

In the given case , magnetic field is towards the viewer of the screen and it is increasing , so the induced current will have to create magnetic field in opposite to it . It means magnetic field will be created towards the screen into it . So the current will be induced in clockwise direction . This current will create magnetic field into the screen which will oppose increasing magnetic field out of screen .

7 0

3 years ago

a ball is thrown straight up into the air with a speed of 13 m/s. if the ball has a mass of 0.25 kg, how high does the ball go?

evablogger [386]

<h2>Hello!</h2>

The answer is: 8.62m

There are involved two types of mechanical energy: kinetic energy and potential energy, in two different moments.

<h2>First moment:</h2>

Before the ball is thrown, where the potential energy is 0.

<h2>Second moment: </h2>

After the ball is thrown, at its maximum height, the Kinetic Energy turns to 0 (since at maximum height,the speed is equal to 0) and the PE turns to its max value.

Therefore,

$E=PE+KE$

Where:

$PE=m.g.h$

$KE=\frac{1*m*v^{2}}{2}$

<em>E</em> is the total energy

<em>PE</em> is the potential energy

<em>KE</em> is the kinetic energy

<em>m</em> is the mass of the object

<em>g</em> is the gravitational acceleration

<em>h </em>is the reached height of the object

<em>v</em> is the velocity of the object

Since the total energy is always constant, according to the Law of Conservation of Energy, we can write the following equation:

$KE_{1}+PE_{1}=KE_{2}+PE_{2}$

Remember, at the first moment the PE is equal to 0 since there is not height, and at the second moment, the KE is equal to 0 since the velocity at maximum height is 0.

$\frac{1*m*v^{2}}{2}+m.g.(0)=\frac{1*m*0^{2}}{2}+m.g.h\\\frac{1*m*v_{1} ^{2}}{2}=m*g*h_{2}$

So,

$h_{2}=\frac{1*m*v_{1} ^{2}}{2*m*g}\\h_{2}=\frac{1*v_{1} ^{2}}{2g}=\frac{(\frac{13m}{s})^{2} }{2*\frac{9.8m}{s^{2}}}\\h_{2}=8.62m}$

Hence,

The height at the second moment (maximum height) is 8.62m

Have a nice day!

5 0

4 years ago