The fraction of the original amount remaining is closest to 1/128
<h3>Determination of the number of half-lives</h3>
- Half-life (t½) = 4 days
- Time (t) = 4 weeks = 4 × 7 = 28 days
- Number of half-lives (n) =?
n = t / t½
n = 28 / 4
n = 7
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 100 g
- Number of half-lives (n) = 7
- Amount remaining (N)=?
N = N₀ / 2ⁿ
N = 100 / 2⁷
N = 0.78125 g
<h3>How to determine the fraction remaining </h3>
- Original amount (N₀) = 100 g
- Amount remaining (N)= 0.78125 g
Fraction remaining = N / N₀
Fraction remaining = 0.78125 / 100
Fraction remaining = 1/128
Learn more about half life:
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Mass =70 ( Mass of protons=1 ,Mass of neutrons =1, Mass of electron =0.0005(can be ignored))
Therefore, 40 +30=70
Charge= -2 ( it is taking in/attracting electrons to its shell) base on the proton number you are able to identify if it is attracting or releasing an electron, if the electron number is more than proton number then it is attracting therefore resulting in a negative charge vice versa for releasing an electron.
Hey there!
We use the Clapeyron equation :
P * V = n * R * T
2.45 * V = 0.500 * 0.0821 * 303
2.45 * V = 12.43815
V = 12.43815 / 2.45
V = 5.07 L
hope this helps !
Answer:
Solution III < Solution II < Solution I < Solution IV
Explanation:
I)
Due to the rate of neutralization is 1 mol of NaOH with 1 mol of HCl and that we have equal volumes of both solution with the same concentration, they neutralize each other leaving a neutral pH (pH=7). Althought, because your titrating agent is a base the equivalence point will be a bit alkaline.
II) The same as the point I) but now the titrating agent is the acid, the equivalence point will be neutral trending a bit to acid.
III) Given that we have one strong acid neutralizing a weak base solution, in the equivalence point the the pH will be acid because the HCl (strong) dissociates compleately so we will have the 0.01 mol (100 ml of 0.1 M) of HCl with 0.01 mol>CH3NH2 (because is a weak base). How much less than 0.01 mol we have? <u>It depends of the strengh of the base and the pH will also depend on that</u>.
IV) This case is similar to the last one but with a strong base and a weak acid. So with a similar deduction the pH in the equivalence point will be alkaline (pH>7). How much? It depends on the strengh of the acid.
<u>In order of increasing pH: </u>
Solution III < Solution II < Solution I < Solution IV