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2 years ago

Explain how the immune system responds to pathegons

Chemistry

1 answer:

Ne4ueva [31]2 years ago

4 0

Answer:

The immune system responds to antigens by producing cells that directly attack the pathogen, or by producing special proteins called antibodies. Antibodies attach to an antigen and attract cells that will engulf and destroy the pathogen. The main cells of the immune system are lymphocytes known as B cells and T cells.

You might be interested in

How is a covalent bond different from an ionic bond?

Alex17521 [72]

A covalent bond is a form of chemical bonding between two non-metals, whereas ionic bonding is a bond between a metal and a non-metal.

8 0

2 years ago

The one factor that a scientist changes in an experiment is called the

Gala2k [10]

Answer:

It might be responding variable.

8 0

3 years ago

You have 1 mole of a gas at STP. If you apply the ideal gas law what is the approximate volume of the gas?

goldfiish [28.3K]

Answer:

A) 22.4L

Explanation:

we know, ideal gas law states

PV=nRT

V=nRT/P

At STP,

T= 273.15K P=1atm R=0.082L.atm/mol/K n=1 mole

V=(1*0.082*273.15)/ 1

V=22.4L

7 0

2 years ago

Now that you have exercised, walked your

ASHA 777 [7]

Answer: The moles of melatonin are 0.000043

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

Given mass of melatonin = 0.01 g

Molar mass of melatonin $(C_{13}H_{16}N_2O_2)$ = 232.28 g/mol

$\text{Number of moles of melatonin}=\frac{0.01 g}{232.28g/mol}=0.000043mol$

Thus the moles of melatonin in 0.01 g are 0.000043

4 0

2 years ago

Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm8 at 27 ∘C. (R =

maxonik [38]

Answer:

Total pressure = 56.77 bar

Explanation:

Given data:

Mass of dioxygen = 8 g

Mass of dihydrogen = 4 g

Volume of vessel = 1 dm³

Temperature = 27°C (27+273 = 300 K)

R = 0.083 bar.dm³ / mol.K

Total pressure = ?

Solution:

Number of moles of dioxygen:

Number of moles = mass/molar mass

Number of moles = 8 g/ 32 g/mol

Number of moles = 0.25 mol

Pressure of dioxygen:

PV = nRT

P = nRT/V

P = 0.25 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³

P = 6.97 bar.dm³ /1 dm³

P = 6.97 bar

Number of moles of dihydrogen:

Number of moles = mass/molar mass

Number of moles = 4 g/ 2 g/mol

Number of moles = 2 mol

Pressure of dihydrogen:

PV = nRT

P = nRT/V

P = 2 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³

P = 49.8 bar.dm³ /1 dm³

P = 49.8 bar

Total pressure of mixture in a vessel:

Total pressure = P (O₂) + P(H₂)

Total pressure = 6.97 bar + 49.8 bar

Total pressure = 56.77 bar

7 0

3 years ago