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Tpy6a [65]
3 years ago
6

In order to improve the condition of your muscular system, you could participate in aerobic activity at least __________. A. 3 m

inutes 5 times a week B. 10 minutes 4 times a week C. 30 minutes 3 times a week D. 50 minutes 3 times a week   Please select the best answer from the choices provided. A B C D
Chemistry
2 answers:
lara [203]3 years ago
8 0
The answer is C. 
30 mins 3 times a week. 
zlopas [31]3 years ago
5 0
I think it would be C
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A voltaic cell is created by using a copper cathode and a magnesium anode. The cathode is immersed in a solution of Cu2 ions, an
Vikki [24]

Answer:

As the reaction proceeds in the given voltaic cell, the Na₂SO₄ present in the salt bridge will dissociate into Na⁺ and SO₄²⁻ ions. As the copper ions in the solution are being deposited on the copper cathode as neutral copper atoms, the solution will become more negative, therefore the Na⁺ ions in the salt bridge will migrate into the the solution in order to maintain electrical neutrality. At the anode, as the Mg metal dissolve into the solution as Mg⁺² ions, the  solution will tend to become more positive. Therefore, the SO₄²⁻ ions present in the salt bridge will migrate into the solution in order to maintain electrical neutrality.

Explanation:

A voltaic or galvanic cell is an example of an electrochemical cell.

An electrochemical cell is a device that produces an electric current from chemical reactions occuring within it.

Electrochemical cells have two electrodes; the anode and the cathode. The anode is defined as the electrode where oxidation occurs while the cathode is the electrode where reduction occurs.

The voltaic cell uses two different metal electrodes each immersed in an electrolyte solution. The two electrodes are connected to each other by means of a wire which allows the flow of electrons from the anode to the cathode. The electrolytes are connected by means of a salt bridge which is a junction that connects the electrolytic solution in the anode and cathode compartment. The salt bridge usually consists of a strong electrolyte like NaCl, KCl, Na₂SO₄, etc.

The electrolyte in the salt bridge serves two purposes: it completes the circuit by providing a path for electron flow and it maintains electrical neutrality in both solutions by allowing ions to migrate between them.

As the reaction proceeds in the given voltaic cell above, the Na₂SO₄ present in the salt bridge will dissociate into Na⁺ and SO₄²⁻ ions. As the copper ions in the solution are being deposited on the copper cathode as neutral copper atoms, the solution will become more negative, therefore the Na⁺ ions in the salt bridge will migrate into the the solution in order to maintain electrical neutrality. Also, at the anode, as the Mg metal dissolve into the solution as Mg⁺² ions, the  solution will tend to become more positive. Therefore, the SO₄²⁻ ions present in the salt bridge will migrate into the solution in order to maintain electrical neutrality.

5 0
3 years ago
How is light produced in an atom?
Nadya [2.5K]

Answer:

light is the result of electrons moving between defined energy levels in an atom called shells.

Explanation:

when something exited an atom like collision with another atom or a chemical reaction, an electron may absorb energy boosting it to a higher level shell.

3 0
3 years ago
2 reasons why recycling aluminium is a good idea
Mazyrski [523]

Answer:

Recycling aluminium saves around 95% of the energy needed to make the metal from raw materials. Along with the energy savings, recycling aluminium saves around 95% of the greenhouse gas emissions compared to the 'primary' production process.

Explanation:

7 0
3 years ago
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32.33 mL of 1.031 M potassium hydroxide were required to reach the endpoint of a titration of 50.00 mL of nitric acid. What was
tester [92]

The molar concentration of the nitric acid solution was 0.6666 mol/L.

<em>Balanced equation</em>: KOH + HNO_3 → KNO_3 + H_2O

<em>Moles of KOH</em>: 32.33 mL KOH × (1.031 mmol KOH /1 mL KOH)

= 33.33 mmol KOH

<em>Moles of HNO_3</em>: 33.33 mmol KOH× (1 mmol HNO_3/1 mmol KOH)

= 33.33 mmol HNO_3

<em>Concentration of KOH</em>: <em>c </em>= "moles"/"litres" = 33.33 mmol/50.00 mL

= 0.6666 mol/L

4 0
3 years ago
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