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dmitriy555 [2]
3 years ago
9

The bond enthalpy in NO is 632 kJ/mol and that of each NO bond in NO2 is 469 kJ/mol. Explain the difference in bond enthalpies b

etween the two molecules.
1. NO has a double bond while in NO2 the bonds are equivalent due to resonance.
2. NO has a single bond while in NO2 the bonds are equivalent due to resonance.
3. Double bonds always have a larger bond enthalpy than single bonds.
4. The bond type does not explain the dif- ference.
Chemistry
1 answer:
Ivanshal [37]3 years ago
5 0

Answer:

1

Explanation:

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Sulfur reacts with fluorine to produce three different compounds. The mass ratio of fluorine to sulfur for each compound is give
NARA [144]

Answer:

Explanation:

Mass of F / Mass of S = 2.962/1 =2.962 X 32 / 32 = 94.78/32

Mass of F / Mass of S = 2.370 /1 = 2.370 X 32 / 32 = 75.84 /32

Mass of F /Mass of S = 3.555/1 = 3.555 x 32 / 32 = 113.76 / 32 .

Now constant mass of S that is 32 g reacts with different mass of F. They are as follows :

94.78 g , 75.84 g , and 113.76 g

Their ratio = 94.78 : 75.84 : 113.76

divide them by 19

their ratio = 5 : 4 : 6

So these data are consistent with law of multiple proportion.

8 0
3 years ago
Help please asap. chem sucks
luda_lava [24]

I'm assuming that C is carbon.

4.590 \: mol \: c \times  \frac{12.01 \:g \: c}{1 \: mol \: c}

55.1259 g of C

6 0
3 years ago
The enthalpy change for converting 1.00 mol of ice at -50.0°c to water at 70.0°c is __________ kj. the specific heats of ice, wa
kogti [31]
First, calculate for the amount of heat used up for increasing the temperature of ice.

      H = mcpdT
       H = (18 g)*(2.09 J/g-K)(50 K) = 1881 J

Then, solve for the heat needed to convert the phase of water.
    H = (1 mol)(6.01 kJ/mol) = 6.01 kJ = 6010 J

Then, solve for the heat needed to increase again the temperature of water.
    H = (18 g)(4.18 J/gK)(70 k)
    H = 5266.8 J

The total value is equal to 13157.8 J

Answer: 13157.8 J
8 0
3 years ago
Write the two half-equations for the following redox reaction <br> 2H+ +2Br- +H2SO4= Br2 + SO2 +2H2O
Oduvanchick [21]

Explanation:

bbdjsjakkakajdjehejkskssjsjjanzbh

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7 0
3 years ago
Elements that have the following qualities: Lustrous, Solid at Room Temperatures, They react and form Basic Compounds, Great con
Tatiana [17]

Answer:

They are classified as METALS.

Explanation:

Elements are simple substances that cannot be chemically broken down into smaller substances. Based on different characteristics, they are classified into 3 namely:

- metals

- non metals and

- metalloid( mainly act as semi- conductor).

METALS are the type of elements that loses electrons to form positive ion, that is, they are electropositive elements. They are distinguished by the following characteristics:

- LUSTROUS: they have the ability to reflect light from its surface.

- At room temperature: Metals are solid are room temperature with the exception of Mercury which is liquid at room temperature.

- They react and form Basic Compounds

- Great conductor: most metals are great conductors of heat and electricity because they possess free electrons.

- Melting Point: they have high melting points.

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3 years ago
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