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8_murik_8 [283]
3 years ago
10

Help me please thank you​

Mathematics
1 answer:
lilavasa [31]3 years ago
3 0

Answer:

22 m^2

Step-by-step explanation:

The area of the bottom rectangle is A = l*w

The length is 8 and width is 2

A = 8*2 =16

The area of the top rectangle is A = l*w

The length is 3 and width is 2

A = 3*2 =6

Adding the areas together

A = 16+6 = 22

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Which of the following is one solution to the expression (ax + b)(cx - d) = 0 ?
V125BC [204]
We know that
if <span>(ax + b)(cx - d) = 0
then
</span><span>(ax + b)= 0-----> ax=-b------> x=-b/a
and
</span><span>(cx - d) = 0-----> cx=d------> x=d/c

therefore

the answer is the option
</span><span>C. -\frac{b}{a}</span>
4 0
3 years ago
A person in a casino decides to play 3 games of blackjack. let w denote a win and l denote a loss. define the event a as "the pe
Ann [662]

Answer: The answer is {(w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l), (l, w, w)}.



Step-by-step explanation: Given that a person in the casino is going to play 3 games of blackjack. Here, 'w' denotes a win and 'l' denotes a loss.  

Also, let 'A' be the event that the person wins at least one game of blackjack. Then, the outcomes of Event 'A' are

(i) win in 1st game     loss in 2nd game       loss in 3rd game

(ii) win in 1st game     win in 2nd game        loss in 3rd game

(iii) win in 1st game     loss in 2nd game       win in 3rd game

(iv) win in 1st game     win in 2nd game        win in 3rd game

(v) loss in 1st game     loss in 2nd game       win in 3rd game

(vi) loss in 1st game     win in 2nd game        loss in 3rd game

(vii) loss in 1st game     win in 2nd game       win in 3rd game

Thus, the outcomes of the event A are (w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l) and (l, w, w).

Thus, A = {(w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l), (l, w, w)}.


5 0
2 years ago
DE=2x <br> EF=2x-6<br> DF=3x+5<br> What is DE
Nataly_w [17]

Answer:

DE=2x you kinda put the answer

Step-by-step explanation:

5 0
3 years ago
Solve for a<br>5+14a=9a-5 a=​
poizon [28]

Answer:

-2

Step-by-step explanation:

5+14a=9a-5

+5      +5

10+14a=9a

-9a      -9a

10+5a=0

-5a   -5a

10= -5a

÷5   ÷5

2= -a

*-1  *-1

-2=a

4 0
3 years ago
NO LINKS!! Find an nth-degree polynomial function with real coefficient satisfying the given conditions.
Sati [7]

n=3; We need a third degree polynomials with the following given zero's: 2 and 5i are zeros; f(-1)=156.

Since these are solutions

x = 2 ; x = 5i. Since imaginaries travel in pairs, the other answer is x= -5i.

We have (x-2)(x-5i)(x+5i) = 0

Now,

f(-1) = (-1-2)(-1-5i)(-1+5i) = 156.

f(-1) = (-3)(26) = -78.

But -78 x -2 = 156, so our polynomial becomes

Y= -2x (<em>x</em> - 2 ) x (<em>x </em>to the power of 2 + 25) = 0

6 0
2 years ago
Read 2 more answers
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