Answer:
1. NaI Y AgI
2. K2S Y CuS
3. K2CO3 N
Explanation:
1. When we add NaI to the mixture, the reaction that takes place is:
- NaI(aq) + Ag⁺(aq) → AgI(s) + Na⁺(aq)
Such a reaction does not happen with Cu⁺².
2. When we add K₂S to the mixture, the reaction that takes place is:
- K₂S(aq) + Cu⁺²(aq) → CuS(s) + 2K⁺(aq)
Such a reaction does not happen with Ag⁺.
3. When we add K₂CO₃ to the mixture, the reactions that take place are:
- K₂CO₃(aq) + 2Ag⁺(aq) → Ag₂CO₃(s) + 2K⁺(aq)
- K₂CO₃(aq) + Cu⁺²(aq) → CuCO₃(s) + 2K⁺(aq)
This means both Cu⁺² and Ag⁺ would precipitate, thus they would not be separated.
Answer:
In ionic compounds, electrons are transferred between atoms of different elements to form ions. But this is not the only way that compounds can be formed. Atoms can also make chemical bonds by sharing electrons equally between each other. Such bonds are called covalent bonds.
Please mark as brainliest please
<span>Molarity is expressed as
the number of moles of solute per volume of the solution. We calculate as follows:
2.80 g ( 1 mol / 56.11 g ) = 0.05 mol KOH
Molarity = 0.05 mol KOH / 750 mL ( 1 L / 1000 mL )
Molarity = 0.07 M
Hope this answers the question. Have a nice day.</span>
Answer:
best answer is D
Explanation:
if element has even number then protons and neutrons are same but if element has odd number then we should add 1 number in number of protons to know neutrons. but this rule is not work in 4 element that element are argon, nitrogen, hydrogen and one other
Answer:
0.0400 g for the example given below.
Explanation:
pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.
- By definition, .
- NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation: .
- From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH: .
- Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain: .
- We also know that . Take the antilog of both sides: .
- Solve for the mass of NaOH: .
Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain: