Answer:
34 m/s
Explanation:
m = Mass of glider with person = 680 kg
v = Velocity of glider with person = 34 m/s
= Mass of glider without person = 680-60 kg
= Gliders speed just after the skydiver lets go
= Mass of person = 60 kg
= Velcotiy of person = 34 m/s
As the linear momentum of the system is conserved
The gliders speed just after the skydiver lets go is 34 m/s
Answer:20 minutes
Explanation:
06:58am - 06:38am =20 minutes
Explanation:
Formula to represent thrust is as follows.
F = 
= 
or, p = 
F = 
= 
= 201.67 N
Thus, we can conclude that the thrust is 201.67 N.
The conversion factor you use is 100 cm = 1 m.
You can divide 20 by 100 to get the answer.
20 cm/100 cm =.2 m
Hope this helped!
To finish one orbit it will take 98 x 60 seconds. So; <span>(2 x pi)/(98 x 60) = 1.07 x 10^-3 rad/sec. </span><span>
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