Answer:
the final velocity of the car is 59.33 m/s [N]
Explanation:
Given;
acceleration of the car, a = 13 m/s²
initial velocity of the car, u = 120 km/h = 33.33 m/s
duration of the car motion, t = 2 s
The final velocity of the car in the same direction is calculated as follows;
v = u + at
where;
v is the final velocity of the car
v = 33.33 + 13 x 2
v = 59.33 m/s [N]
Therefore, the final velocity of the car is 59.33 m/s [N]
Gravity increases when mass increases and distance decreases. Gravity decreases when mass decreases and distance increases.
Answer:
6666.67 Newtons
Explanation:
The formula F=ma (force is equal to mass multiplied by acceleration) can be used to calculate the answer to this question.
In this case:
- mass= 0.1mg= 1*10^-7 kg
- velocity= 4.00*10^3 m/s
- time= 6.00*10^-8 s
Using velocity and time, acceleration can be calculated as:
Substituting these values into the formula F=ma, the answer is:
- F= (1*10^-7)kg * (6.667*10^10) m/s²
- F= 6666.67 Newtons of force
Answer:15.8 m/s
Explanation:
Given
Gravitational Force
Air resistance
mass of Parachutist
Velocity after
Now Parachutist opens the parachute
Net for on Parachutist
drag force
therefore deceleration
velocity after 10 s is
Magnitude of displacement is equal to the square root of point A^2 + point B^2
So take the first point and square it, then take the second point and square it, add them together, then take the square root of their sum. What do you get?