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ExtremeBDS [4]
3 years ago
6

Numbered 8 nowwwwwww

Physics
1 answer:
amm18123 years ago
7 0

Torque =  r x F

|F| =  mg =  60 * 10 N = 600 N ( assuming g ~ 10m/s^2)

distance of fulcrum = torque / Force = 90/600 m = .15 m.

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A ball is dropped from a high rise platform at t=0 starting from rest. After 6 seconds another ball is thrown downwards from the
AlekseyPX

Answer:

73.5 m/s

Explanation:

The position of the first ball is:

y = y₀ + v₀ t + ½ at²

y = h + (0)(18) + ½ (-9.8)(18)²

y = h − 1587.6

The position of the second ball is:

y = y₀ + v₀ t + ½ at²

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